FINDING EQUATION OF QUADRATIC FUNCTION FROM GRAPH WORKSHEET

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Determine the equation of quadratic function from graph. Give the function in general form.

Problem 1 :

Solution

Problem 2 :

Solution

Problem 3 :

Solution

Problem 4 :

Solution

Problem 5 :

Solution

Example 6 :

The area of a rectangle is modeled by the graph where y is the area (in square meters) and x is the width (in meters). Write an equation of the parabola. Find the dimensions and corresponding area of one possible rectangle. What dimensions result in the maximum area?

quadratic-equation-from-roots-q2.png

Solution

Example 7 :

Every rope has a safe working load. A rope should not be used to lift a weight greater than its safe working load. The table shows the safe working loads S (in pounds) for ropes with circumference C (in inches). Write an equation for the safe working load for a rope. Find the safe working load for a rope that has a circumference of 10 inches.

quadratic-equation-from-roots-q3.png

Solution

Answer key

1)  y = -x2 + 5x - 4

2)  y = x2 - 5x + 4

3)  y = -3x2 - 9x + 12

4)  y = 2x2 + 6x - 8

5)  y = 2x2 - 10x + 8

6)  the rectangle with dimension with the measure of 3.5 m by 3.5 m. 

7) y = 180x2

Determine the equation of quadratic function from graph. Give the function in vertex form.

Problem 1 :

quadraticfunctionfromgraphq6

Solution

Problem 2 :

quadraticfunctionfromgraphq7

Solution

Problem 3 :

quadraticfunctionfromgraphq8

Solution

Problem 4 :

quadraticfunctionfromgraphq9

Solution

Problem 5 :

Which function represents the widest parabola? Explain your reasoning.

a) y = 2(x + 3)2        b)  y = x2 − 5     c)  y = 0.5(x − 1)2 + 1      d)  y = −x2 + 6

Solution

Problem 6 :

The graph of which function has the same axis of symmetry as the graph of

y = x2 + 2x + 2?

a) y = 2x2 + 2x + 2       b)  y = −3x2− 6x + 2

c)  y = x2 − 2x + 2       d)  y = −5 x2+ 10x + 2

Solution

Problem 7 :

The path of a diver is modeled by the function

f(x) = −9x2 + 9x + 1

where f(x) is the height of the diver (in meters) above the water and x is the horizontal distance (in meters) from the end of the diving board.

a. What is the height of the diving board?

b. What is the maximum height of the diver?

c. Describe where the diver is ascending and where the diver is descending.

quadratic-equation-from-roots-q4.png

Solution

Answer Key

1) The equation of the parabola is y = x2 + 1.

2)  the equation of the parabola is y = (x + 3)2 - 1

3) the equation of the parabola is y = x2 - 2

4)  the equation of the parabola is y = 1(x - 1)2 + 1.

5)  c)  y = 0.5(x − 1)2 + 1 

6) b)  y = −3x2− 6x + 2

7) a) height of the board is 1 meter.

b) Reaches the maximum height at 0.5 seconds and the height is 3.25 m

c) When x > 0.5, it is increasing and x < 0.5 it is decreasing.

Find the equation of each parabola.

Problem 1 :

equationfromtransformedqfq1

Solution

Problem 2 :

equationfromtransformedqfq2

Solution

Problem 3 :

equationfromtransformedqfq3

Solution

Problem 4 :

equationfromtransformedqfq4

Solution

Problem 5 :

equationfromtransformedqfq5

Solution

Problem 6 :

equationfromtransformedqfq6

Solution

Problem 7 :

Describe the transformation of the graph of the parent quadratic function. Then identify the vertex. 

f(x) = 2(x + 3)2 + 2

Solution

Problem 8 :

write a rule for g described by the transformations of the graph of f. Then identify the vertex.

f(x) = x2

vertical stretch by a factor of 4 and a reflection in the x-axis, followed by a translation 2 units up

Solution

Problem 9 :

Match the function with its graph. Explain your reasoning.

a) g(x) = 2(x − 1)2 − 2

b) g(x) = 1/2 ( x + 1)2 − 2

c) g(x) = −2(x − 1)2 + 2

d) g(x) = 2(x + 1)2 + 2

e) g(x) = −2(x + 1)2 − 2

f) g(x) = 2(x − 1)2 + 2

quadratic-function-with-transformation-q1

Solution

Answer Key

1) the equation from the given graph is 

y = -1x2 + 4

2) the equation from the given graph is 

y = (x + 3)2

3)  the equation from the given graph is 

y = -(x - 3)2 + 3

4) y = 1(x - 2)2 - 3

5) y = (x - 2)2 + 1

6) y = (x + 2)2 - 1

7) 

  • Vertical stretch of 2
  • Moving the parabola 2 units up
  • Moving the parabola 3 units left.
  • Vertex is (-3, 2)

8)  f(x) = -4(x + 2)2

9)

a) g(x) = 2(x − 1)2 − 2  ----> Option C

b) g(x) = 1/2 ( x + 1)2 − 2 ----> Option B

c) g(x) = −2(x − 1)2 + 2   ----> Option D

d) g(x) = 2(x + 1)2 + 2  ----> Option E

e) g(x) = −2(x + 1)2 − 2   ----> Option F

f) g(x) = 2(x − 1)2 + 2   ----> Option A

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