WORD PROBLEMS ON PERIMETER OF 2D SHAPES WORKSHEET

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Problem 1 :

A farmer decides to fence a 400 m by 350 m field with a 4-strand wire fence. Find :

a) The perimeter of the field

b)  The total length of wire required

c) The total cost of wire required if a single strand of wire costs 12.4 cents per metre.

Solution

Problem 2 :

Boxes containing computers are fastened with three pieces of tape, as shown.

Each piece of tape is overlapped 5 cm at the join. Calculate the total length of tape required for 20 boxes.

Solution

Problem 3 :

The minute hand of a clock is 8 cm long. How far does the tip travel between 2.00 pm and 2.45 pm?

Solution

Problem 4 :

Which is the shorter path from A to B :

Around the 2 smaller semi-circles or around the large semi-circle?

Solution

Problem 5 :

A machine makes circular paper plates which have circumference 50 cm. find the diameter of a plate correct to the nearest mm.

Solution

Problem 6 :

A bicycle wheel has diameter 0.6 m.

a) Find the circumference of the wheel to the nearest mm.

b) Through how many revolutions must the wheel turn during a 100 km trip?

Solution

Problem 7 :

a)   Find the perimeter P of the figure alongside, giving your answer in simplest form.

b)   If the perimeter of the figure is 30 cm:

i)  Find x

ii)  Find the length of the longest side.

Solution

Problem 8 :

Length of a rectangular field is 220 m and width is 130 m. If a man runs around this field 3 times, find the distance covered by him?

Solution

Problem 9 :

Rahul walks around a square park once and covers 800 m. What will be the area of the park ?

Solution

Problem 10 :

The area of a rectangular field is 1600 sqm. If the length of the field is 80 m, find the perimeter of the field?

problems-on-2d-shapes-q1

Solution

Answer Key

1)  a) 1500 m  b) 6000 m  c) $ 74400

2)  77 m

3)  37.7 cm

4)  Both are same.

5)  d = 15.9 cm

6)  a)  C = 1.884 m  b)  53078 revolutions

7)  (i)  x = 4   (ii) longest side = 8 cm.

8) Distance covered by the man = 2100 m

9) Area of the park = 40000 square meter

10) Perimeter =  200 meter

11) Perimeter of the parallelogram =  24 cm

Find the perimeter of the following:

Problem 1 :

perimeterof2dshapeq1

Solution

Problem 2 :

perimeterof2dshapeq2

Solution

Problem 3 :

perimeterof2dshapeq3

Solution

Problem 4 :

perimeterof2dshapeq4

Solution

Problem 5 :

perimeterof2dshapeq5

Solution

Problem 6 :

perimeterof2dshapeq6

Solution

Problem 7 :

Kim decides to get fit by running laps of a nearby shopping complex. Its dimensions are shown in the diagram alongside.

How many laps does he have to complete to run 13 km in total?

perimeterof2dshapeq7

Solution

Problem 8 :

A rectangular field measured 290 m by 210 m. How long will it take for a girl to go two times round the field, if she walks at the rate of 1.5 m/s ?

Solution

Problem 9 :

A wire is in the shape of a rectangle whose length is 40 cm and breadth is 22 cm .If same wire is bent in the shape of square ,what will be the measure of each side ? Also find which shape encloses more area.

Solution

Problem 10 :

The triangle and square have the same perimeter. Find x

2d-shape-word-problems-q1

Solution

Problem 11 :

An isosceles triangle has a perimeter of 73cm.

An equilateral triangle has a perimeter of 51cm

The triangles are put together to make a kite.

2d-shape-word-problems-q2.png

Workout the perimeter of the kite.

Solution

Answer Key

1) perimeter of a triangle is 15 cm

2)  perimeter of a rectangle is 22 cm.

3) perimeter of a triangle is 30 cm.

4) Perimeter of a Trapezoid is 26 cm.

5) perimeter of a triangle is 30 cm.

6)  perimeter of shapes is 19.4 cm.

7) 5 laps

8) she will take approximately 22 minutes.

9)  the shape square covers more area.

10)  the side length of the square is 12 cm.

11)  Perimeter of the kite = 107 cm

Problem 1 :

missinglengthfromperiq1

Solution

Problem 2 :

missinglengthfromperiq2

Solution

Problem 3 :

missinglengthfromperiq3

Solution

Problem 4 :

missinglengthfromperiq4.png

Solution

Problem 5:

missinglengthfromperiq5

Solution

Problem 6 :

missinglengthfromperiq6.png

Solution

Problem 7 :

missinglengthfromperiq7

Solution

Problem 8:

missinglengthfromperiq8

Solution

Problem 9 :

missinglengthfromperiq9

Solution

Problem 10 :

If length and width of a rectangular is halved then its area will be _______

Solution

Problem 11 :

The wire of length 84 m is converted into a square then broken to form a rectangle of length 30 m. Find the width of the rectangle.

Solution

Problem 12 :

The ratio of lengths of two rectangular fields is 4 : 3 and the ratio of their widths is 3 : 2. Find the ratio of their areas.

Solution

Problem 13 :

The area of a square is 3/4 times area of a rectangle and width of the rectangle is 1/4 times of its length. Find the area of the square if the sum of length and width of the rectangle is 15 m

Solution

Problem 14 :

The length of the diagonal of a square is 50. Find the perimeter of a square.

Solution

Answer Key

1) The length of the missing side is 5 cm.

2) The length of the missing side is 26 cm.

3) The length of the missing side is 5 cm.

4) The length of the missing side is 7 cm

5) The length of the missing side is 12 cm.

6) The length of the missing side is 22 cm.

7) The length of the missing side is 13.5 cm.

8) The length of the missing side is 0.4 m.

9) The length of the missing side is 37 cm.

10) Area of new rectangle will be 1/4 of area of old rectangle.

11) the width of the rectangular shape is 12 m

12)  2 : 1

13) 27 square meter

14) 20 units.

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