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Write as a single logarithm in the form log k:
Problem 1 :
log 6 + log 5
Problem 2 :
log 10 - log 2
Problem 3 :
2 log 2 + log 3
Problem 4 :
log 5 - 2 log 2
Problem 5 :
1/2 log 4 - log 2
Problem 6 :
log 2 + log 3 + log 5
Problem 7 :
log 20 + log (0.2)
Problem 8 :
- log 2 - log 3
Problem 9 :
3 log (1/8)
Problem 10 :
4 log 2 + 3 log 5
Problem 11 :
6 log 2 - 3 log 5
Problem 12 :
1 + log 2
Problem 13 :
1 - log 2
Problem 14 :
2 - log 5
Problem 15 :
3 + log 2 + log 7
Problem 16 :
Find the value of log2 4 log4 6 log6 8
Problem 17 :
log3 243 = 2x + 1
Problem 18 :
log6 36 = 5x + 3
Problem 19 :
e-2x+1 = 13
Problem 20 :
log5(x2 + x + 4) = 2
|
1) log 30 2) log 5 3) log 12 4) log (5/4) 5) 0 6) log 30 7) 2 log 2 8) - log 6 9) -9 log 2 10) log 2000 |
11) log (64/125) 12) log 20 13) log 5 14) log 20 15) log (14000) 16) 3 17) x = 2 18) x = -1/5 19) x = -0.78 20) (-1 Β± β85)/2 |
Solve the following logarithmic equations :
Problem 1 :
log7 3 + log7 x = log7 32
Problem 2 :
2 log6 4x = 0
Problem 3 :
log2 x + log2 (x - 3) = 2
Problem 4 :
log2 (x + 5) - log2 (x - 2) = 3
Problem 5 :
4 ln (2x + 3) = 11
Problem 6 :
log x - log 6 = 2 log 4
Problem 7 :
log 2x = 1.5
Problem 8 :
log2 2x = -0.65
Problem 9 :
1/3 log2 x + 5 = 7
Problem 10 :
4 log5 (x + 1) = 4.8
Problem 11 :
log2 x + log2 3 = 3
Problem 12 :
2 log4 x - log4 (x - 1) = 1
Solve the equation. Check for extraneous solutions.
Problem 13 :
ln (7x β 4) = ln (2x + 11)
Problem 14 :
log2(x β 6) = 5
Problem 15 :
log 5x + log (x β 1) = 2
Problem 16 :
log4(x + 12) + log4 x = 3
|
1) x = 32/3 2) x = 1/4 3) x = 4 or x = -1 4) x = 3 5) x = 6.321 6) x = 96 7) x = 15.81 8) x = 0.32 |
9) x = 26 10) x = 5.90 11) x = 8/3 12) x = 2 13) x = 3 14) x = 38 15) x = -4 and x = 5 16) x = 4 and x = -16 |
Solve the following logarithmic equations.
Problem 1 :
ln x = -3
Problem 2 :
log(3x - 2) = 2
Problem 3 :
2 logx = log2 + log(3x - 4)
Problem 4 :
log x + log(x - 1) = log(4x)
Problem 5 :
log3(x + 25) - log3(x - 1) = 3
Problem 6 :
log9(x - 5) + log9(x + 3) = 1
Problem 7 :
log x + log(x - 3) = 1
Problem 8 :
log2(x - 2) + log2(x + 1) = 2
Problem 9 :
Given that
2 log3(x - 5) - log3(2x - 13) = 1
Show that x2 - 16x + 64 = 0 and solve for x.
Problem 10 :
a) Find the positive value of x such that
log x64 = 2
b) Solve for x
log2(11 - 6x) = 2log2(x - 1) + 3
Problem 11 :
Given that a and b are positive constants, solve the simultaneous equations
a = 3b
log3 a + log3 b = 2
Give your answers as exact numbers.
1) x = e-3
2) x = 34
3) x = 4, x = 2
4) x = 0, x = 5
5) x = 2
6) x = 6, x = -4
7) x = 5 or x = -2
8) x = 3 or x = -2
9) x = 8 and x = 8
10) a) x = 8
b) x = -1/4 and x = 3/2
11) a = 3β3 and a = -3β3, b = β3 and -β3
Use the One-to-One Property to solve the equation for x.
Problem 1 :
log2(x + 1) = log2 4
Problem 2 :
log2(x - 3) = log2 9
Problem 3 :
log(2x + 1) = log 15
Problem 4 :
log(5x + 3) = log 12
Problem 5 :
ln(x + 2) = ln 6
Problem 6 :
ln(x - 4) = ln 2
Problem 7 :
ln(x2 - 2) = ln 23
Problem 8 :
ln(x2 - x) = ln 6
Problem 9 :
A population of 30 mice is expected to double each year. The number p of mice in the population each year is given by p = 30(2n). In how many years will there be 960 mice in the population?
Problem 10 :
Approximate the solution of each equation using the graph
1 β 55 β x = β9

Problem 11 :
Approximate the solution of each equation using the graph
log25x = 2

Problem 12 :
The apparent magnitude of a star is a measure of the brightness of the star as it appears to observers on Earth. The apparent magnitude M of the dimmest star that can be seen with a telescope is
M = 5 log D + 2
where D is the diameter (in millimeters) of the telescopeβs objective lens. What is the diameter of the objective lens of a telescope that can reveal stars with a magnitude of 12?
Problem 13 :
A biologist can estimate the age of an African elephant by measuring the length of its footprint and using the equation
β = 45 β 25.7eβ0.09a
where β is the length (in centimeters) of the footprint and a is the age (in years).
a. Rewrite the equation, solving for a in terms of β.
b. Use the equation in part (a) to find the ages of the elephants whose footprints are shown.

1) x = 3
2) x = 12
3) x = 7
4) x = 9/5
5) x = 4
6) x = 6
7) x = Β±5
8) x = 3 or x = -2
9) the required number of years is 5.
10) x = 3.56
11) x = 0.8
12) the required diameter is 100 millimeter.
13) a) a = (1/0.09) ln [25.7/(45 - l)]
b) 12 years, 8 years, 5 years, 2 years
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May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM