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To convert standard form to vertex form, we may follow the different ways.

From the standard form of the equation, y = ax2 + bx + c
(i) Take the coefficient of x2, from all the terms if there is.
(ii) Write the coefficient of x as a multiple of 2.
(iii) Get any one of the algebraic identities (a+b)2 or (a-b)2
Example :
Convert the following quadratics from standard form to vertex form
y = 2x2 – 4x + 8
Solution :
y = 2x2 – 4x + 8
Factor 2.
y = 2(x2 – 2x + 4)
Write the coefficient of x as a multiple of 2.
y = 2(x2 – 2⋅x⋅1 + 12 - 12 + 4)
Here x2 – 2⋅x⋅1 + 12 matches with a2 – 2⋅a⋅b + b2 = (a - b)2
y = 2[(x - 1)2 - 1 + 4]
y = 2[(x - 1)2 + 3]
Distributing 2, we get
y = 2(x - 1)2 + 6
From the standard form of the equation, y = ax2 + bx + c
(i) Take the coefficient of x2, from all the terms if there is.
(ii) Take half of the coefficient of x and write it as (x - a)2 or (x + a)2. Here a is half the coefficient of x.
Example :
Convert y = x2 - 4x + 3 into factored form.
Solution :
y = x2 - 4x + 3
Coefficient of x2 is 1, so dont have to factor anything.
Half of the coefficient of x is 2.
y = (x - 2)2 - 22 + 3
y = (x - 2)2 - 4 + 3
y = (x - 2)2 - 1
Complete the square to convert the standard form quadratic function into vertex form. Then
find the vertex.
Example 1 :
f(x) = x2 + 4x - 14
Solution :
Coefficient of x2 is 1. So, don't have to factorize.
Write the coefficient of x as multiple of 2.
f(x) = x2 + 2 ⋅ x ⋅ 2 + 22 - 22 - 14
f(x) = (x+2)2 - 4 - 14
f(x) = (x+2)2 - 18
Vertex of the parabola is (-2, -18).
Example 2 :
f(x) = 2x2 + 9x
Solution :
Coefficient of x2 is 2.
Write the coefficient of x as multiple of 2.
Vertex of the parabola is (9/4, -81/8).
Example 3 :
f(x) = 5x2 - 4x + 1
Solution :
Coefficient of x2 is 5. So, we have to factorize 5.
Vertex of the parabola is (2/5, 1/5).
Example 4 :
f(x) = x2 - 16x + 70
Solution :
Coefficient of x2 is 1. So, don't have to factorize.
Write the coefficient of x as multiple of 2.
f(x) = x2 - 2 ⋅ x ⋅ 8 + 82 - 82 + 70
f(x) = (x - 8)2 - 64 + 70
f(x) = (x - 8)2 + 6
Vertex of the parabola is (8, 6).
Example 5 :
f(x) = -3x2 + 48x - 187
Solution :
Coefficient of x2 is -3. So, factorize -3.
f(x) = -3[x2 - 16x] - 187
Write the coefficient of x as multiple of 2.
f(x) = -3[x2 - 2 ⋅ x ⋅ 8 + 82- 82] - 187
f(x) = -3[(x - 8)2- 64] - 187
f(x) = -3(x - 8)2+ 192 - 187
f(x) = -3(x - 8)2+ 5
Vertex of the parabola is (8, 5).
Example 6 :
The parabola shows the path of your first golf shot, where x is the horizontal distance (in yards) and y is the corresponding height (in yards).

The path of your second shot is modeled by the function
f(x) = −0.02x(x − 80)
Which shot travels farther before hitting the ground? Which travels higher?
Solution :
By observing the graph, it is clear that the ball will reach the horizontal distance of 100 yards
f(x) = −0.02x(x − 80)
Midpoint of the x-coordinates of x-intercepts is the x-coordinate of the vertex.
−0.02x(x − 80) = 0
x = 0 and x = 80
= (0 + 80)/2
= 80/2
= 40
Applying x = 40 in f(x) = −0.02x(x − 80)
f(40) = −0.02(40)(40 - 80)
= 0.8(40)
= 32
The maximum height of the second shot is 32 yards.
Because 100 yards > 80 yards, the first shot travels farther.
Because 32 yards > 25 yards, the second shot travels higher.
To check that the second shot travels higher, graph the function representing the path of the second shot and the line y = 25, which represents the maximum height of the first shot. The graph rises above y = 25, so the second shot travels higher.
Example 7 :
Tell whether the function f(x) = −4x2 − 24x − 19 has a minimum value or a maximum value. Then find the value.
Solution :
f(x) = −4x2 − 24x − 19
a = -4, b = -24 and c = -19
x = -b/2a
= 24/-8
x = -3
Applying x = -3. we get
f(-3) = −4(3)2 − 24(3) − 19
= -4(9) - 72 - 19
= -36 - 72 - 19
= -127
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May 21, 24 08:51 PM
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