SURFACE AREA OF SIMILAR SOLIDS WORKSHEET

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Each pair of figures is similar. Use the information given to find the scale factor of the figure on the left to the figure on the right. 

Problem 1 :

Solution

Problem 2 :

Solution

Problem 3 :

The solids are similar. Find the surface area S of the shaded shape.

Solution

Problem 4 :

The pyramids are similar. What is the surface area of Pyramid A?

Solution

Problem 5 :

Find the surface area of smaller cuboid.

Solution

Problem 6 :

Find the surface area of large cylinder.

Solution

Problem 7 :

The ratio of the corresponding linear measures of two similar cans of fruit is 4 to 7. The smaller can has a surface area of 220 square centimeters. Find the surface area of the larger can.

Solution

Problem 8 :

A and B are mathematically similar.

The height of A : the height of B = 3 : 5

(a) Find the surface area of A : the surface area of B

(b) Find the volume of A : the volume of B

Solution

Problem 9 :

A, B and C are similar.

  • The volume of A is 729 cm³ and the volume of B is 64 cm³.
  • The surface area of B is 25 cm² and the surface area of C is 121 cm².
  • Find the ratio length of A : length of B : length of C

Solution

Problem 10 :

Shapes A, B and C are similar.

  • The height of shape A is 8 cm.
  • The height of shape C is 4cm.
  • The ratio of the surface area of shape B to the surface area of shape C is 25:9
  • Work out the ratio of the volume of shape A to shape B.
surface-area-of-similar-shapes-q1

Solution

Answer Key

1)  6 : 5

2)  1 : 5

3)  S = 352 m2

4)  s = 216 ft2

5)  s = 237.5 m2

6)  S = 171.875 cm2

7) the required surface area of large can is 385 square cm.

8) a) Ratio between surface area of cylinders is = 9 : 25

b) Ratio between volume of cylinders is = 27 : 125

9) a : b : c = 49 : 28 : 16

10) 216 : 27

The solids are similar. Find the surface area S of the red solid. Round your answer to the nearest tenth.

Problem 1 :

Solution

Problem 2 :

Solution

Problem 3 :

The ratio of the corresponding linear measures of two similar cans of fruit is 4 to 7. The smaller can has a surface area of 220 square centimeters. Find the surface area of the larger can

Solution

Problem 4 :

A model of sky scraper was made with the scale factor of  3 : 13. What is the ratio of the surface area of model to the surface area of original sky scrapers?

Solution

Problem 5 :

Each pair of figures is similar. Find the scale factor of the figure on the left to the figure on the right. Then find

(i)  the ratio of surface areas

and

(ii)  the ratio of volumes.

Solution

Problem 6 :

Solution

Problem 7 :

Cylinders A and B are similar.

  • The height of A is 6 cm.
  • The volume of A is 240 cm³ to 2 significant figures.
  • The height of B is 15 cm and the volume of B is y.

Work out the error interval of y. 

Solution

Problem 8 :

The square based pyramid A is divided into Pyramid B and Frustum C.

similar-figures-wp-q6.png

(a) Express the volume of Pyramid B as a fraction of the volume of Pyramid A.

(b) Express the volume of Frustum C as a fraction of the volume of Pyramid A

Solution

Problem 9 :

Ornament A and B are mathematically similar. They are solid and both made from copper and zinc in the ratio 3:2

  • Ornament A has a height of 5 cm and volume of 30 cm³
  • Ornament B has a height of 18 cm. The density of copper is 8.96 g/cm³
  • The density of zinc is 7.13 g/cm³

Work out the difference in mass between ornament A and ornament B.

Solution

Answer Key

1)  surface area of large solid  = 756 m2

2)  surface area of small solid = 1012.5 in2

3) Surface area of large can =  673.75 sq cm

4)  Ratio between surface area of model to original sky scraper = 9 : 169

5) i) the ratio of surface area is = 25 : 16

ii) the ratio of volume is 125 : 64 = 125 : 64

6) i) the ratio of surface area is 49:16 = 49:16

ii) The volume of these two prism will be in the ratio = 343 : 64

7) Volume of cylinder B is 3750 cm3

8) a) Volume of Pyramid B : volume of Pyramid A = 1 : 24

(b) Volume of Frustum C : volume of Pyramid A = 1 : 2

9) Difference between the mass = 11269.70 grams

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