Find the extraneous solution for the radical equations given below.
1) √(x + 4) = x - 2 Solution
2) √(10x + 9) = x + 3 Solution
3) √(2x + 5) = √(x + 7) Solution
4) √(x + 6) – 2 = √(x – 2) Solution
Solve the following radical equations with rational exponents.
1) 2x(2/3) = 8 Solution
2) 4x(3/2) = 32 Solution
3) x1/4 + 3 = 0 Solution
4) 2x3/4 - 14 = 40 Solution
5) (x + 6)1/2 = x Solution
6) (5 - x)1/2 – 2x = 0 Solution
7) 2(x + 11)1/2 = x + 3 Solution
8) (5x2 – 4)1/4 = x Solution
9) x1/5 = 2 Solution
10) 2√(3x – 1) + 3 = 11 Solution
11) 4x2 = 64 Solution
12) 2(x – 2)4 – 3 = 159 Solution
13) √(2x + 4) = √(x + 2) Solution
14) ∛x – 6 = -2 Solution
Solve the following radical equations.
1) √(x + 1) = 4 Solution
2) √(2t + 15) = t Solution
3) √(2t + 15) = t Solution
4) √(2 – x) = x - 2 Solution
5) √s2 – 1 = √5s – 5 Solution
6) ∛x = 4 Solution
7) ∜(2p + 2) = 3 Solution
8) ∛x + 1 = ∛x2 - 5 Solution
9) √(2 - √x) = √x Solution
10) √3t + 1 + √5 – t = 4 Solution
Solve the following radical equation
1) √(4x + 1) = √(x + 10) Solution
2) √(3x – 3) - √(x + 12) = 0 Solution
3) ∛2x – 5 - ∛8x + 1 = 0 Solution
4) ∛(x + 5) = 2∛(2x + 6) Solution
5) √(3x – 8) + 1 = √(x + 5) Solution
6) √(x + 2) = 2 - √x Solution
7) √(2x + 4) = √(x + 2) Solution
Solve the following radical equations.
1) 3√x + 3 = 15 Solution
2) 4√x - 1 = 3 Solution
3) √(x + 3) = 5 Solution
4) √(3x + 4) = 4 Solution
5) √(2x + 3) - 7 = 0 Solution
6) √(6 - 3x) - 2 = 0 Solution
7) x1/4 - 1 = 0 Solution
8) (x - 2)1/3 = -5 Solution
9) x1/3 - 2 = 0 Solution
10) √3x = 6 Solution
11) (2x + 7)1/2 - x = 2 Solution
12) √4x - 8 = 0 Solution
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM