Asymptotes are lines that the curve approaches at the edges of the coordinate plane.
Types of asymptotes :
Horizontal Asymptotes :
A horizontal asymptote is a horizontal line that is not part of a graph of a function but guides it for x – values “far” to the right and/or “far” to the left. The graph may cross it but eventually, for large enough or small enough values of x (approaching ±∞), the graph would get closer and closer to the asymptote without touching it.
A horizontal asymptote is a special case of a slant asymptote.
Let
deg N(x) = the degree of a numerator
and
deg D(x) = the degree of a denominator
Case 1 :
Degree of numerator = degree of denominator
y = leading coefficient of N(x)/leading coefficient of D(x).
Case 2 :
Degree of numerator < degree of denominator
y = 0, which is the x – axis.
Case 3 :
degree of numerator > degree of denominator
There is no horizontal asymptote.
Vertical Asymptotes :
The Vertical Asymptotes of a rational function are found using the zeros of the denominator.
Oblique or slant asymptote :
A slant (oblique) asymptote occurs when the polynomial in the numerator is a higher degree than the polynomial in the denominator.
To find the slant asymptote you must divide the numerator by the denominator using either long division or synthetic division.
Find the horizontal asymptote of the graph of each rational function.
Problem 1 :
y = 2/(x – 6)
Solution :
y = 2/(x – 6)
Degree of numerator = 0
Degree of denominator = 1
degree of numerator < degree of denominator
So, equation of the horizontal asymptote is y = 0 which is the x – axis.
Problem 2 :
y = (x + 2)/(x – 4)
Solution :
y = (x + 2)/(x – 4)
Degree of numerator = 1
Degree of denominator = 1
degree of numerator = degree of denominator
y = leading coefficient of N(x)/leading coefficient of D(x).
So, equation of the horizontal asymptote is y = 1.
More problems on horizontal asymptotes
Describe the vertical asymptotes and holes for the graph of each rational function.
Problem 3 :
y = (x - 2)/(x + 2) (x - 2)
Solution :
y = (x - 2)/(x + 2) (x - 2)
We see x – 2 as a common factor in both numerator and denominator.
After cancel x – 2. We get,
1/(x + 2)
To find vertical asymptote, we equate the denominator to 0.
x + 2 = 0
x = -2
We see the hole at x = 2 in the graph.
x – 2 = 0 we will get hole at x = 2.
So, the vertical asymptote at x = -2; hole at x = 2.
More problems on vertical asymptotes
Find the oblique asymptote of the rational function
Problem 4 :
f(x) = (x2 + 8x – 20)/(x – 1)
Solution :
f(x) = (x2 + 8x – 20)/(x – 1)
y = (x + 9) -11/(x – 1)
So, the oblique asymptote of the rational function is
y = x + 9
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