PRACTICE ON MATRICES AND DETERMINANTS WORKSHEET

Problem 1 :

If |adj(adj A)| = |A|9, then the order of the square matrix A is

(1)  3     (2)  4     (3)  2    (4)  5

Solution

Problem 2 :

If A is a 3 × 3 non - singular matrix such that AAT = AT A and B = A-1 AT, then BBT

(1)  A     (2)  B     (3)  I3    (4)  BT

Solution

Problem 3 :

If A = 3 5 12, B = adj A and C = 3A, then |adj B|C =

(1)  1/3      (2)  1/9    (3)  1/4      (4)  1

Solution

Problem 4 :

If A = 1 -2 14 = 6 0 06, then A = (1) 1 -2 14 (2) 1 2 -14 (3) 4 2 -11 (4) 4 -1 21

Solution

Problem 5 :

If A = 7 3 42, then 9I2 - A =

(1) A-1       (2) A-1/2      (3) 3A-1    (4)  2A-1

So, option 4) is correct.

Solution

Problem 6 :

If A = 2 0 15 and B = 1 4 20 then |adj (AB)| =

1) -40     2) -80     3) -60      4) -20

Solution

Answer Key

1) 4

2) I3

3)  1/9

4)  

5)  2A^-1

6) -80

Problem 1 :

If P=1x013024-2 is the adjoint of 3×3 matrix A and |A|=4, then x is

(1) 15     (2) 12     (3) 14     (4) 11

Solution

Problem 2 :

If A=31-12-2012-1 and A-1=a11a12a13a21a22a23a31a32a33 then the value of a23 is

(1) 0     (2) -2     (3) -3     (4) -1

Solution

Problem 3 :

If A, B and C are invertible matrices of some order, then which one of the following is not true?

(1) adj A = | A | A-1               (2) adj (AB) = (adj A)(adj B)

(3) det A-1 = (det A)-1           (4) (ABC)-1 = C-1B-1A-1

Solution

Problem 4 :

If (AB)-1=12-17-1927 and A-1=1-1-23, then B-1=
(1) 2-5-38
(3) 3121
(2) 8532
(4) 8-5-32

Solution

Problem 5 :

If AT A-1 is symmetric, then A2

(1) A-1     (2) (AT)    (3) AT     (4) (A-1)2

Solution

Problem 6 :

If A is a non-singular matrix such that A-1=53-2-1, then AT-1=
(1) -5321
(3) -1-325
(2) 53-2-1
(4) 5-23-1

Solution

Answer Key

1) x = 11

2) a23 = -1

3)  adj (AB) = (adj A)(adj B)

4)  option (1)

5)  A2 = (AT)2

6)  Option (4)

Problem 1 :

The augmented matrix of a system of linear equations is 1 2 73014600𝜆-7𝜇 + 5.The system has infinitely many solutions if

Solution

Problem 2 :

Let A = 2-11-12-11-12 and 4B = 31-113x-113.

Solution

Problem 3 :

If A = 3 -3 42-340-11, then adj(adj A) is
(1) 3 -3 42-340-11
(2) 6 -6 84-680-22
(3) -3 3 -4-23-401-1
(4) 3 -3 40-112-34

Solution

Problem 4 :

If xayb = em, xcyd = en, Δ1 = mbnd, Δ2 = amcn, Δ3 = abcd, then the values of x and y are respectively,

(1) e(Δ21), e(Δ31)

(2) log (Δ21), log(Δ31)

(2) log (Δ13), log(Δ23)

(4) e13), e23)

Solution

Problem 5 :

Which of the following is/are correct ?

(i) Adjoint of a symmetric matrix is also a symmetric matrix.

(ii) Adjoint of a diagonal matrix is also a diagonal matrix.

(iii) If A is a square matrix of order n and λ is a scalar, then adj(λA) = λnadj(A)

(iv) A(adj A) = (adj A)A = |A|I

(i)  Only (i)  (2) (ii) and (iii)  (3)  (iii) and (iv)  (4)  (i), (ii) and (iv)

Solution

Problem 6 :

If ρ(A) = ρ([A/B]), then the system AX = B of linear equations is

(1)  consistent and has a unique solution

(2) consistent 

(3)  consistent and has infinitely many solution

(4)  inconsistent

Solution

Problem 7 :

If 0 ≤ θ ≤ π and the system of equations x + (sin θ)y – (cos θ)z = 0, (cos θ)x – y + z = 0, (sin θ)x + y – z = 0 has a non – trivial solution then θ is

(1) 2𝜋3
(2) 3𝜋4
(3) 5𝜋6
(4) 𝜋4

Solution

Answer Key

1)  (4)  λ = 7,  μ = -5

2)  (4) x = 1

3)  option 1

4)  (4) e13), e23)

5)  option (4) is correct. 

6)  option (2) is correct.

7) 𝜋/4

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