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Find x and y intercepts of the lines given below.
Problem 1 :
x + 2y = 8
Problem 2 :
3x - y = 6
Problem 3 :
2x - 3y = 6
Problem 4 :
4x + 3y = 12
Problem 5 :
x + y = 5
Problem 6 :
x - y = - 5
Problem 7 :
2x - y = - 4
Problem 8 :
9x - 2y = 9
Problem 9 :
3x + 4y = -15
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x-intercept : 1) x = 8 2) x = 2 3) x = 3 4) x = 3 5) x = 5 6) x = - 5 7) x = -2 8) x = 1 9) x = -5 |
y-intercept : 1) y = 4 2) y = -6 3) y = -2 4) y = 4 5) y = 5 6) y = 5 7) y = 4 8) y = -9/2 9) y = -15/4 |
Use axes intercepts to draw the graph of:
Problem 1 :
x + y = 6
Problem 2 :
2x + y = 4
Problem 3 :
3x - y = 5
Problem 4 :
2x + 3y = 6
Problem 5 :
3x - 4y = 12
Problem 6 :
x + 3y = -6
Problem 7 :
2x - 5y = 10
Problem 8 :
2x + 7y = 14
Problem 9 :
3x - 4y = 8
Problem 10 :
You are designing a sticker to advertise your band. A company charges $225 for the first 1000 stickers and $80 for each additional 1000 stickers.
a. Write an equation that represents the total cost (in dollars) of the stickers as a function of the number (in thousands) of stickers ordered.
b. Find the total cost of 9000 stickers.
Problem 11 :
You pay a processing fee and a daily fee to rent a beach house. The table shows the total cost of renting the beach house for different numbers of days.

a. Can the situation be modeled by a linear equation? Explain.
b. What is the processing fee? the daily fee?
c. You can spend no more than $1200 on the beach house rental. What is the maximum number of days you can rent the beach house?
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x-intercept : 1) (6, 0) 2) (2, 0) 3) (5/3, 0) 4) (3, 0) 5) (4, 0) 6) (-6, 0) 7) (5, 0) 8) (7, 0) 9) (8/3, 0) |
y-intercept : 1) (0, 6) 2) (0, 4) 3) (0, -5) 4) (0, 2) 5) (0, -3) 6) (0, -2) 7) (0, -2) 8) (0, 2) 9) (0, -2) |
10) a) y = 2x/25 - 145
b) the required cost is $575.
11) a) y = 97x + 52
b) Processing fee is $52 and daily fee is $97.
c) Approximately 20 days.
Find the x and y intercept of the line with the given equation.
Problem 1 :
x - y = 4
Problem 2 :
x + 5y = -15
Problem 3 :
3x - 4y = -12
Problem 4 :
2x - y = 10
Problem 5 :
4x - 5y = 20
Problem 6 :
-6x + 8y = -36
Problem 7 :
You are planning an awards banquet for your school. You need to rent tables to seat 180 people. There are two table sizes available. Small tables seat 6 people, and large tables seat 10 people. The equation 6x + 10y = 180 models this situation, where x is the number of small tables and y is the number of large tables.
a. Graph the equation. Interpret the intercepts.
b. Find four possible solutions in the context of the problem.
Problem 8 :
You are organizing a class trip to an amusement park. The cost to enter the park is $30. The cost to enter with a meal plan is $45. You have a budget of $2700 for the trip. The equation
30x + 45y = 2700
models the total cost for the class to go on the trip, where x is the number of students who do not choose the meal plan and y is the number of students who do choose the meal plan.

a. Interpret the intercepts of the graph.
b. Describe the domain and range in the context of the problem.
1)
x -intercept (a) = 4
y -intercept (b) = - 4
2)
x -intercept (a) = - 15
y -intercept (b) = - 3
3)
x -intercept (a) = - 4
y -intercept (b) = 3
4)
x -intercept (a) = 5
y -intercept (b) = - 10
5)
x -intercept (a) = 5
y -intercept (b) = - 4
6)
x -intercept (a) = 6
y -intercept (b) = - 9/2
7)
a) The x-intercept shows that you can rent 30 small tables when you do not rent any large tables. The y-intercept shows that you can rent 18 large tables when you do not rent any small tables.
b) four possible combinations of tables that will seat 180 people are 0 small and 18 large, 10 small and 12 large, 20 small and 6 large, and 30 small and 0 large.
8) a) This means if all 60 students choose the meal plan, the budget is fully utilized.
b)
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May 21, 24 08:51 PM
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