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To find x and y-intercept of a line, we have two ways.
Method 1 :
(i) To find x-intercept, apply y = 0. Then write the coordinate as (x, 0).
(ii) To find y-intercept, apply x = 0. Then write the coordinate as (0, y).
Method 2 :
Convert the equation from standard form to intercept form.
(x/a) + (y/b) = 1
a = x-intercept and b = y-intercept
Here we see examples using the first method.
To get examples using second method, please click here
Find x and y intercepts of the lines given below.
Problem 1 :
x + 2y = 8
Solution:
|
x-intercept : y = 0 x + 2y = 8 x + 0 = 8 x = 8 |
y-intercept : x = 0 0 + 2y = 8 2y = 8 y = 4 |
So, x-intercept is 8 and y-intercept is 4.
Problem 2 :
3x - y = 6
Solution :
|
x-intercept : y = 0 3x - y = 6 3x - 0 = 6 3x = 6 x = 2 |
y-intercept: x = 0 0 - y = 6 -y = 6 y = -6 |
So, x-intercept is 2 and y-intercept is -6.
Problem 3 :
2x - 3y = 6
Solution :
|
x-intercept : y = 0 2x - 3y = 6 2x - 0 = 6 2x = 6 x = 3 |
y-intercept : x = 0 0 - 3y = 6 -3y = 6 y = -2 |
So, x-intercept is 3 and y-intercept is -2.
Problem 4 :
4x + 3y = 12
Solution :
|
x-intercept : y = 0 4x + 3y = 12 4x + 0 = 12 4x = 12 x = 3 |
y-intercept : x = 0 0 + 3y = 12 3y = 12 y = 4 |
So, x-intercept is 3 and y-intercept is 4.
Problem 5 :
x + y = 5
Solution :
|
x-intercept : y = 0 x + y = 5 x + 0 = 5 x = 5 |
y-intercept : x = 0 0 + y = 5 y = 5 |
So, x-intercept is 5 and y-intercept is 5.
Problem 6 :
x - y = - 5
Solution :
|
x-intercept : y = 0 x - y = - 5 x - 0 = - 5 x = - 5 |
y-intercept : x = 0 0 - y = - 5 -y = -5 y = 5 |
So, x-intercept is -5 and y-intercept is 5.
Problem 7 :
2x - y = - 4
Solution :
|
x-intercept : y = 0 2x - y = - 4 2x - 0 = - 4 2x = -4 x = -2 |
y-intercept : x = 0 0 - y = - 4 -y = - 4 y = 4 |
So, x-intercept is -2 and y-intercept is 4.
Problem 8 :
9x - 2y = 9
Solution :
|
x-intercept : y = 0 9x - 2y = 9 9x - 0 = 9 9x = 9 x = 1 |
y-intercept : x = 0 0 - 2y = 9 -2y = 9 y = -9/2 |
So, x-intercept is 1 and y-intercept is -9/2.
Problem 9 :
3x + 4y = -15
Solution :
|
x-intercept : y = 0 3x + 4y = -15 3x + 0 = -15 3x = -15 x = -5 |
y-intercept : x = 0 0 + 4y = -15 4y = -15 y = -15/4 |
So, x-intercept is -5 and y-intercept is -15/4.
Problem 10 :
The school band is selling sweatshirts and baseball caps raise $9000 to attend a band competition. Sweatshirts cost $25 each and base ball caps cost $10 each. The equation 25x + 10y = 9000 models this situation, where x is the number of sweatshirts sold and y is the number of baseball caps sold.
a) Find and interpret the intercepts
b) If 258 sweatshirts are sold, how many baseball caps are sold ?
c) Graph the equation. Find one more possible solutions in the context of the problem.
Solution :
25x + 10y = 9000
a) Interpreting intercepts :
|
x-intercept : Put y = 0 Applying y = 0, we get 25x = 9000 x = 9000/25 x = 360 |
y-intercept : Put x = 0 Applying x = 0, we get 10y = 9000 y = 9000/10 y = 900 |
Maximum number of sweatshirts sold is 360
Maximum number of baseball caps sold is 900
b) When x = 258
25(258) + 10y = 9000
6450 + 10y = 9000
10y = 9000 - 6450
10y = 2550
y = 2550/10
y = 255
c)

(200, 400) is one of the possible solution.
Problem 11 :
Your club is ordering enrollment gifts engraved with your club logo. Key chains cost $5 each. Wristbands cost $2 each. You have a budget of $150 for the gifts. The equation
5x + 2y = 150
models the total cost, where x is the number of key chains and y is the number of wristbands.
a. Graph the equation. Interpret the intercepts.
b. Your club decides to order 18 key chains. How many wristbands can you order?
Solution :
5x + 2y = 150
a)
|
x-intercept : Put y = 0 5x = 150 x = 150/5 x = 30 |
y-intercept : Put x = 0 2y = 150 y = 150/2 y = 75 |
The maximum number of wristbands is 30
The maximum number of key chains is 75.
b) 5x + 2y = 150
When x = 18
5(18) + 2y = 150
90 + 2y = 150
2y = 150 - 90
2y = 60
y = 60/2
y = 30
So, the number of wristbands is 30.
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