GRAPH A LINE USING X AND Y INTERCEPTS

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Use axes intercepts to draw the graph of:

Problem 1 :

x + y = 6

Solution :

x-intercept:

Put y = 0

x + y = 6

x + 0 = 6

x = 6

(6, 0)

y-intercept:

Put x = 0

0 + y = 6

y = 6

(0, 6)

Plot (6, 0) and (0, 6) by connecting these two points, we will get the line.

Problem 2 :

2x + y = 4

Solution :

x-intercept:

y = 0

2x + y = 4

2x + 0 = 4

2x = 4

x = 2

(2, 0)

y-intercept:

x = 0

0 + y = 4

y = 4

(0, 4)

Plot (2, 0) and (0, 4) by connecting these two points, we will get the line.

Problem 3 :

3x - y = 5

Solution :

x-intercept:

y = 0

3x - y = 5

3x - 0 = 5

3x = 5

x = 5/3

(5/3, 0)

y-intercept:

x = 0

0 - y = 5

y = -5

(0, -5)

Plot (5/3, 0) and (0, -5) by connecting these two points, we will get the line.

Problem 4 :

2x + 3y = 6

Solution :

x-intercept  :

y = 0

2x + 0 = 6

2x = 6

x = 3

(3, 0)

y-intercept :

x = 0

0 + 3y = 6

3y = 6

y = 2

(0, 2)

Plot (3, 0) and (0, 2) by connecting these two points, we will get the line.

Problem 5 :

3x - 4y = 12

Solution :

x-intercept :

y = 0

3x - 4y = 12

3x - 0 = 12

3x = 12

x = 4

(4, 0)

y-intercept :

x = 0

0 - 4y = 12

-4y = 12

y = -3

(0, -3)

Plot (4, 0) and (0, -3) by connecting these two points, we will get the line.

Problem 6 :

x + 3y = -6

Solution :

x-intercept :

y = 0

x + 0 = -6

x = -6

(-6, 0)

y-intercept :

x = 0

0 + 3y = -6

3y = -6

y = -2

(0, -2)

Plot (-6, 0) and (0, -2) by connecting these two points, we will get the line.

Problem 7 :

2x - 5y = 10

Solution :

x-intercept :

y = 0

2x - 0 = 10

2x = 10

x = 5

(5, 0)

y-intercept :

x = 0

0 - 5y = 10

-5y = 10

y = -2

(0, -2)

Plot (5, 0) and (0, -2) by connecting these two points, we will get the line.

Problem 8 :

2x + 7y = 14

Solution :

x-intercept:

Put y = 0

2x + 0 = 14

2x = 14

x = 7

(7, 0)

y-intercept :

x = 0

0 + 7y = 14

7y = 14

y = 2

(0, 2)

Plot (7, 0) and (0, 2), by connecting these two points, we will get the line.

Problem 9 :

3x - 4y = 8

Solution :

x-intercept:

y = 0

3x - 0 = 8

3x = 8

x = 8/3

(8/3, 0)

y-intercept:

x = 0

0 - 4y = 8

-4y = 8

y = -2

(0, -2)

Plot (8/3, 0) and (0, -2),  by connecting these two points, we will get the line.

Problem 10 :

You are designing a sticker to advertise your band. A company charges $225 for the first 1000 stickers and $80 for each additional 1000 stickers.

a. Write an equation that represents the total cost (in dollars) of the stickers as a function of the number (in thousands) of stickers ordered.

b. Find the total cost of 9000 stickers.

Solution :

a) Let x be the number of stickers and y be the charge.

(1000, 225) and (2000, 305)

Slope = (y2 - y1) / (x2 - x1)

= (305 - 225) / (2000 - 1000)

= 80/1000

= 2/25

Equation of line :

(y - y1) = m(x - x1)

(y - 225) = (2/25)(x - 1000)

y = 2x/25 - (2/25) ⋅ 1000 + 225

y = 2x/25 - 2 ⋅ 40 + 225

y = 2x/25 - 80 + 225

y = 2x/25 - 145

b) Total cost of 9000 stickers.

y = 2(9000)/25 - 145

= 720 - 145

= 575

So, the required cost is $575.

Problem 11 :

You pay a processing fee and a daily fee to rent a beach house. The table shows the total cost of renting the beach house for different numbers of days.

x-and-y-intercept-q1

a. Can the situation be modeled by a linear equation? Explain.

b. What is the processing fee? the daily fee?

c. You can spend no more than $1200 on the beach house rental. What is the maximum number of days you can rent the beach house?

Solution :

Let be the number of days and y be the total cost

(2, 246) and (4, 450)

Slope = (y2 - y1) / (x2 - x1)

= (450 - 246) / (4 - 2)

= 194/2

= 97

Equation of line :

(y - y1) = m(x - x1)

(y - 246) = 97(x - 2)

y = 97x - 194 + 246

y = 97x + 52

b) Processing fee is $52 and daily fee is $97.

c) Amount spend = 2000

2000 = 97x + 52

97x = 2000 - 52

97x = 1948

x = 1948/97

x = 20.08

Approximately 20 days.

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