Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.
Evaluate each of the following logarithms without the use of a calculator.
|
1) log4 1/2 = 2) log6 1/36 = 3) log2/3 9/4 = 4) log81 1/27 = |
5) log4 1/8 = 6) log36 1/6 = 7) log1/16 32 = 8) log27 1/3 = 9) log1/4 16 = |
Problem 10 :
Expand the logarithmic expression :
ln (5/12x)
Problem 11 :
Use the properties of logarithms to condense each expression :
a) 3 log 4 − 2 log 𝑘
b) −5 log2 (𝑥 +1) + 3 log2 (6𝑥)
c) (1/3) log4 10 + (1/3) log4 ℎ − 6 log4 𝑔
d) ln (3𝑚 +5) − 4 ln 𝑚 − ln (𝑚 − 1)
e) log 20 + 2 log (1/2) − log 𝑥 + 3 log 𝑦
Problem 12 :
Use properties of logarithms to expand each expression. The expanded logarithm expressions should have arguments with no exponent, product, or quotient
a) ln (4/5)
b) log63x
c) log 7b/√c
d) log2(m3/8n)
e) log3[(u - 1)/(v5w3)]
Problem 13 :
Solve each equation.
log4 x = log4 3 + log4 (x − 2)
Problem 14 :
Solve the equation.
ln(𝑥 − 3) + ln(2𝑥 + 3) = ln (−4𝑥2)
Problem 15 :
Solve the equation.
log (3𝑥 + 2) = 1 + 𝑙𝑜𝑔 2𝑥
|
1) x = -1/2 2) x = -2 3) x = -2 4) x = -3/4 5) x = -3/2 6) x = -1/2 7) x = -5/4 8) x = -1/3 9) x = -2 10) ln 5 - ln 12 - ln x |
11) a) log (64/k2) b) log2 [(216𝑥3) / (𝑥 + 1)5] c) log4 [∛(10ℎ) / 𝑔6] d) ln [(3m + 5) / 𝑚4 (𝑚 − 1)] e) log (5 𝑦3/𝑥) 12) a) ln (4/5) = ln 4 - ln 5 b) log63x = log63 + log6x c) log 7 + log b - (1/2) log c d) 3log2m - 3 - log2 n e) log3(u - 1) - 5 log3v - 3 log3w 13) x = 3 14) x = 3/2 and x = -1 15) x = 2/17 |
|
Find : 1) log3 9 2) log2 32 3) log2 √2 4) log4 √2 5) log3 3√3 6) log6 1 |
7) log8 8 8) log8 (1/8) 9) log1/8 (1/8) 10) log√2 (1/√2) 11) log2 (1/√2) 12) log8 (1/√2) |
Problem 13 :
Solve ln (4x − 7) = ln (x + 5)
Problem 14 :
log2(5x − 17) = 3
Problem 15 :
log10(9x + 1) = 3
Problem 16 :
log8√(1 - x) = 1/3
Problem 17 :
Solve the simultaneous equations:
log3 x + log5 y = 6
log3 x - log5 y = 2
Problem 18 :
Solve the equation
3(1 + log x) = 6 + log x
Problem 19 :
Solve log3 [(2 + x) / (2 - x)] = 3
|
1) 2 2) 5 3) 1/2 4) 1/4 5) 3/2 6) 0 7) 1 8) -1 9) 1 |
10) -1 11) -1/2 12) -1/6 13) x = 4 14) x = 5 15) x = 111 16) x = -3 17) x = 9 and y = 625 18) x = 31.6 19) x = 56/3 |
Without using a calculator, simplify.
|
1) log 8 / log 2 2) log 9 / log 3 3) log 4 / log 8 4) log 5 / log (1/5) |
5) log (0.5) / log 2 6) log 8 / log (0.25) 7) log 2b / log 8 8) log 4 / log 2a |
Problem 9 :
Under certain conditions, the wind speed s (in knots) at an altitude of h meters above a grassy plain can be modeled by the function
s(h) = 2 ln 100h
a. By what amount does the wind speed increase when the altitude doubles?
b. Show that the given function can be written in terms of common logarithms as
s(h) = (2 /log e) (log h + 2)
Problem 10 :
-3 ln x = -24
Problem 11 :
4 - 3log (5x) = 16
Problem 12 :
log3(x - 1) = -2
Problem 13 :
log2(x2 - 4) = log2 21
Problem 14 :
The function
s(d) = 0.159 + 0.118 log d
relates the slope, s, of a beach to the average diameter, d, in millimeters, of the sand particles on the beach. Which beach has a steeper slope: beach A, which has d = 0.0625, or beach B, which has very coarse sand with d = 1 ? Justify your decision.
Problem 15 :
The function
S(d) = 93 log d + 65
relates the speed of the wind, S, in miles per hour, near the center of a tornado to the distance that the tornado travels, d, in miles.
a) If a tornado travels a distance of about 50 miles, estimate its wind speed near its center.
b) If a tornado has sustained winds of approximately 250 mph, estimate the distance it can travel.
|
1) 3 2) 2 3) 2/3 4) -1 5) 1 6) -3/2 7) b/3 8) 2/a |
9) a) the wind speed will increase by 1.38 knots. b) (log h2 + 4) / log e 10) x = e8 11) x = 1/50000 12) x = 10/9 13) x = -5 and 5 14) Slope for Beach B > Slope for Beach A 15) a) 222.91 b) Approximately 95 miles |
Find the value of y.
|
1) log5 25 = y 2) log31 = y 3) log16 4 = y 4) log2 (1/8) = y 5) log51 = y 6) log2 8 = y |
7) log7 (1/7) = y 8) log3 (1/9) = y 9) logy 32 = 5 10) log9 y = -1/2 11) log4 (1/8) = y 12) log9 (1/81) = y |
Problem 13 :
Describe the similarities and difference between in solving the equations
45x - 2 = 16 and log4(10x + 6) = 1
Then solve the each equation
Problem 14 :
For a sound with intensity I (in watts per square meter) the loudness L(I) of the sound (in decibels) is given by the function
L(I) = 10 log (I/I0)
Where I0 is the intensity of barely audible sound (about 10-12 watts per square meter) An artist in a recording studio turns up the volume of a track so that the intensity of the sound doubles. By how many decibels does the loudness increase ?
Problem 15 :
The length ℓ (in centimeters) of a scalloped hammerhead shark can be modeled by the function
ℓ = 266 − 219e−0.05t
where t is the age (in years) of the shark. How old is a shark that is 175 centimeters long?
|
1) y = 2 2) y = 0 3) y = 1/2 4) y = -3 5) y = 0 6) y = 3 |
7) y = -1 8) y = -2 9) y = 2 10) y = 1/3 11) y = -3/2 12) y = -2 13) x = -1/5 14) The loudness increases by 10 log 2 decibels or about 3 decibels. 15) Approximately 18 years. |
Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM