Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.
To evaluate logarithmic function, we should know how to convert the logarithmic function into exponential form.

Evaluate each of the following logarithms without the use of a calculator.
Problem 1 :
log4 1/2 =
Solution :
log4 1/2 = x
4x = 1/2
(22)x = 1/2
(2)2x = 2-1
2x = -1
x = -1/2
Problem 2 :
log6 1/36 =
Solution :
log6 1/36 = x
6x = 1/36
6x = 1/62
6x = 6-2
x = -2
Problem 3 :
log2/3 9/4 =
Solution :
log2/3 9/4 = x
(2/3)x = 9/4
(2/3)x = (3/2)²
(2/3)x = (2/3)-²
x = -2
Problem 4 :
log81 1/27 =
Solution :
log81 1/27 = x
81x = 1/27
(34)x = 1/33
(3)4x = 3-3
4x = -3
x = -3/4
Problem 5 :
log4 1/8 =
Solution :
log4 1/8 = x
4x = 1/8
(22)x = 1/23
(2)2x = 2-3
2x = -3
x = -3/2
Problem 6 :
log36 1/6 =
Solution :
log36 1/6 = x
36x = 1/6
(62)x = 1/6
(6)2x = 6-1
2x = -1
x = -1/2
Problem 7 :
log1/16 32 =
Solution :
log1/16 32 = x
(1/16)x = 32
(1/24)x = 25
(2)-4x = 25
-4x = 5
x = -5/4
Problem 8 :
log27 1/3 =
Solution :
log27 1/3 = x
27x = 1/3
(33)x = 1/3
(3)3x = 3-1
3x = -1
x = -1/3
Problem 9 :
log1/4 16 =
Solution :
log1/4 16 = x
(1/4)x = 16
(1/22)x = 24
(2)-2x = 24
-2x = 4
x = -4/2
x = -2
Problem 10 :
Expand the logarithmic expression :
ln (5/12x)
Solution :
= ln (5/12x)
= ln 5 - ln 12x
= ln 5 - [ln 12 + ln x]
= ln 5 - ln 12 - ln x
Problem 11 :
Use the properties of logarithms to condense each expression :
a) 3 log 4 − 2 log 𝑘
b) −5 log2 (𝑥 +1) + 3 log2 (6𝑥)
c) (1/3) log4 10 + (1/3) log4 ℎ − 6 log4 𝑔
d) ln (3𝑚 +5) − 4 ln 𝑚 − ln (𝑚 − 1)
e) log 20 + 2 log (1/2) − log 𝑥 + 3 log 𝑦
Solution :
a) 3 log 4 − 2 log 𝑘
= log 43 − log k2
= log 64 − log k2
= log (64/k2)
b) −5 log2 (𝑥 +1) + 3 log2 (6𝑥)
= 3 log2 (6𝑥) − 5 log2 (𝑥 + 1)
= log2 (6𝑥)3 − log2 (𝑥 + 1)5
= log2 (6)3 (𝑥)3 − log2 (𝑥 + 1)5
= log2 (216𝑥3) − log2 (𝑥 + 1)5
= log2 [(216𝑥3) / (𝑥 + 1)5]
c) (1/3) log4 10 + (1/3) log4 ℎ − 6 log4 𝑔
= log4 ∛10 + log4 ∛ℎ − log4 𝑔6
= log4 (∛10 ∛ℎ) − log4 𝑔6
= log4 (∛10ℎ) − log4 𝑔6
= log4 [∛(10ℎ) / 𝑔6]
d) ln (3𝑚 + 5) − 4 ln 𝑚 − ln (𝑚 − 1)
= ln (3m + 5) − ln 𝑚4 − ln (𝑚 − 1)
= ln (3m + 5) − [ln 𝑚4 + ln (𝑚 − 1)]
= ln (3m + 5) − [ln 𝑚4 (𝑚 − 1)]
= ln [(3m + 5) / 𝑚4 (𝑚 − 1)]
e) log 20 + 2 log (1/2) − log 𝑥 + 3 log 𝑦
= log 20 + log (1/2)2 − log 𝑥 + log 𝑦3
= log 20 + log (1/4) − log 𝑥 + log 𝑦3
= log 20 ⋅ (1/4) ⋅ 𝑦3 − log 𝑥
= log 5 𝑦3 − log 𝑥
= log (5 𝑦3/𝑥)
Problem 12 :
Use properties of logarithms to expand each expression. The expanded logarithm expressions should have arguments with no exponent, product, or quotient
a) ln (4/5)
b) log63x
c) log 7b/√c
d) log2(m3/8n)
e) log3[(u - 1)/(v5w3)]
Solution :
a) ln (4/5) = ln 4 - ln 5
b) log63x = log63 + log6x
c) log 7b/√c = log 7b - log √c
= log 7 + log b - log c1/2
= log 7 + log b - (1/2) log c
d) log2(m3/8n) = log2m3- log28n
= log2m3- [log28 + log2 n]
= 3log2m - [log223+ log2 n]
= 3log2m - [3log22+ log2 n]
= 3log2m - [3(1) + log2 n]
= 3log2m - 3 - log2 n
e) log3[(u - 1)/(v5w3)]
= log3(u - 1) - log3(v5w3)
= log3(u - 1) - [log3v5 + log3w3]
= log3(u - 1) - [5 log3v + 3 log3w]
= log3(u - 1) - 5 log3v - 3 log3w
Problem 13 :
Solve each equation.
log4 x = log4 3 + log4 (x − 2)
Solution :
log4 x - log4 (x − 2) = log4 3
log4 (x/(x − 2)) = log4 3
x/(x - 2) = 3
x = 3(x - 2)
x = 3x - 6
x - 3x = -6
-2x = -6
x = 6/2
x = 3
So, the value of x is 3.
Problem 14 :
ln(𝑥 − 3) + ln(2𝑥 + 3) = ln (−4𝑥2)
Solution :
ln(𝑥 − 3) + ln(2𝑥 + 3) = ln (−4𝑥2)
ln(x - 3)(2x + 3) = ln (−4𝑥2)
(x - 3)(2x + 3) = −4𝑥2
2x2 + 3x - 6x - 9 = −4𝑥2
2x2 + 4𝑥2 - 3x - 9 = 0
6x2 - 3x - 9 = 0
2x2 - x - 3 = 0
a = 2, b = -1 and c = -3
x = [-b ± √(b2- 4ac)]/2a
x = [1 ± √(12- 4(2)(-3))]/2(2)
= [1±√(1 + 24)]/4
= [1±√25]/4
= [1 ± 5]/4
x = (1 + 5)/4 and x = (1 - 5)/4
x = 6/4 and x = -4/4
x = 3/2 and x = -1
Problem 15 :
log (3𝑥 + 2) = 1 + 𝑙𝑜𝑔 2𝑥
Solution :
log (3𝑥 + 2) = 1 + 𝑙𝑜𝑔 2𝑥
log (3𝑥 + 2) - 𝑙𝑜𝑔 2𝑥 = 1
log [(3x + 2)/2x] = 1
(3x + 2)/2x = 101
(3x + 2)/2x = 10
3x + 2 = 10(2x)
3x + 2 = 20x
3x - 20x = -2
-17x = -2
x = 2/17
Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM