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Problem 1 :
Find zero of the polynomial p(x) = x + 3.
Problem 2 :
Find the zeroes of quadratic polynomial x²-5x-6.
Problem 3 :
If 1 is a zero of the polynomial p(x) = ax2 - 3(a-1)x - 1, then find the value of 'a' ? Solution
Problem 4 :
If the graph of a polynomial intersects the x – axis at only one point, can it be a quadratic polynomial? Solution
Problem 5 :
What number should be added to the polynomial x2-5x+4, so that 3 is the zero of the polynomial? Solution
Problem 6 :
If x – 3 and x – 1/3 are both factors of ax2 + 5x + b , show that a = b Solution
Problem 7 :
If y = -1 is a zero of the polynomial q(y) = 4y3 + ky2 - y -1, then find the value of k
Problem 8 :
For what value of m is x3 – 2mx2 + 16 divisible by x + 2
Problem 9 :
If p and q are the zeroes of the quadratic polynomial f(x) = 2x2 - 7x + 3, find the value of p + q - pq
|
1) x = -3 2) 6 and -1 3) a = 1 4) Cannot |
5) 2 6) Proved 7) k = 4 8) m = 1 9) p + q - pq = 2 |
Find the zeroes of quadratic polynomial given below.
Problem 1 :
y = (x - 4)2 - 25
Problem 2 :
y = 2x2 - 9x - 5
Problem 3 :
f(x) = 3x2 + 5x - 12
Problem 4 :
f(x) = (-1/2) (x + 3)2 + 8
Problem 5 :
f(x) = x2 - 24x + 144
Problem 6 :
f(x) = 9x2 - 81
Problem 7 :
f(x) = x2 - x - 20
Problem 8 :
A soccer player kicks a ball downfield. The height of the ball increases until it reaches a maximum height of 8 yards, 20 yards away from the player. A second kick is modeled by
y = x(0.4 − 0.008x)
Which kick travels farther before hitting the ground? Which kick travels higher?
Problem 9 :
Graph the function. Label the x-intercept(s), vertex, and axis of symmetry.
a) y = (x + 3)(x − 3)
b) y = (x + 1)(x − 3)
Problem 10 :
Write the quadratic function f(x) = x2 + x − 12 in intercept form. Graph the function. Label the x-intercepts, y-intercept, vertex, and axis of symmetry.
1) zeroes are 9 and -1
2) zeroes are -1/2 and 5.
3) zeroes are -3 and 4/3.
4) zeroes are -7 and 1.
5) x = 12
6) zeroes are -3 and 3.
7) zeroes are -4 and 5.
8)
Horizontal distance covered by the second kick is 50 yards.
9) a)
b)
10)
Problem 1 :
Write a quadratic equation in standard form with solutions, x = -3 and x = 4. Use integers for a, b and c.
Problem 2 :
Write a quadratic equation in standard form with solutions, x = 2/3 and x = -5. Use integers for a, b and c.
Problem 3 :
Write an equation of the parabola in intercept form y = a(x - p)(x - q) that has x- intercepts of 9 and 1 and passes through (0, -18).
A) y = -1/2(x - 9)(x - 1) B) y = -1/2(x + 9)(x + 1)
C) y = -2(x - 9)(x - 1) D) y = -2(x + 9)(x + 1)
Problem 4 :
Write an equation of the parabola in intercept form y = a(x - p)(x - q) that has x- intercepts of 12 and -6 and passes through (14, 4).
A) y = 1/10(x - 12)(x + 6) B) y = 1/10(x + 12)(x - 6)
C) y = 10(x - 12)(x + 6) D) y = 10(x + 12)(x - 6)
Problem 5 :
Determine the equation of a quadratic function given zeros x = 4 and point (3, 2).
Problem 6 :
Use the intercepts and a point on the graph below to write the equation of the function.

Problem 7 :
Use the intercepts and a point on the graph below to write the equation of the function.

Problem 8 :
The sum and product of zeroes of p(x) = 63x2 - 7x - 9 are S and P respectively. Find the value of S and P. Find the value of 27S + 14P
a) -1 b) 1 c) 2 d) -2
Problem 9 :
If one zero of the quadratic polynomial 2x2 - 8x - m is 5/2, then find the other zero.
a) 1/2 b) 3/2 c) -3/2 d) -1/2
1) x2 - x - 12 = 0
2) 3x2 + 13x - 10 = 0
3) y = -2(x - 9)(x - 1)
4) y = 1/10(x - 12)(x + 6)
5) y = 2(x - 4)(x - 4)
6) y = (x + 6)(x - 6)
7) y = 3(x + 6)(x - 1)
8) 1
9) 3/2
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May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM