1) If 3x - 4(64 - x) = 10 then the value of x is
(a) -266 (b) 133 (c) 66.5 (d) 38
2) If 8x - 3 = 25 + 17x, then x is
(a) a fraction (b) an integer
(c) a rational number (d) cannot be solved
3) The value of x for which the expressions 3x - 4 and 2x + 1 become equal is
(a) -3 (b) 0 (c) 5 (d) 1
4) 8x - 7 - 3x = 6x - 2x - 3
5) 10x - 5 - 7x = 5x + 15 - 8
6) 4t - 3 - (3t + 1) = 5t - 4
7) 5(x - 1) - 2(x + 8) = 0
8) 1 - (x - 2) - [(x - 3) - (x - 1)] = 0
9) 4(3p + 2) – 5(6p - 1) = 2(p - 8) – 6(7p - 4)
10) 3(5x - 7) + 2(9x - 11) = 4(8x - 7) – 111
1) x = 38 2) x is a fraction 3) x = 5 4) x = -4 5) x = -6 |
6) t = 1/4 7) x = 0 8) x = 5 9) p = -5/22 10) x = -68/29 |
1) (3x – 8)/2x = 1
2) 5x/(2x – 1) = 2
3) (2x – 3)/(4x + 5) = 1/3
4) 8/x = 5/(x – 1)
5) [5(1 – x) + 3(1 + x)]/(1 – 2x) = 8
6) [y – (4 – 3y)] / [2y – (3 + 4y)] = 1/5
7) (9 – 3y)/(1 – 9y) = 8/5
8) (3x + 2)/(2x – 3) = -3/4
9) (5x + 1)/(2x) = -1/3
10) (x + 1)/(2x + 7) = 3/8
11) 1/(x-1) + 2/(x+1) = 2
12) (50/x) + 4 = 14
Problem 13 :
you wrote the function c = (50m + 1000)/m, which represents the average cost c (in dollars) of making m models using a 3-D printer. Find how many models must be printed for the average cost per model to fall to $90 by
(a) solving an equation, and
(b) using the inverse of the function.
Problem 14 :
So far this baseball season, you have 12 hits out of 60 times at-bat. Solve the equation 0.360 = (12 + x) / (60 + x) to find the number of consecutive hits you need to raise your batting average to 0.360.
1) x = 8 2) x = 2 3) x = 7 4) x = 8/3 5) x = 0 6) y = 17/22 |
7) y = -37/57 8) x = 1/18 9) x = -3/17 10) x = 13/2 11) x = (3±√17)/4 12) x = 5 13) m = 25 14) the number of consecutive hits is 15. |
Problem 1 :
The sum of three consecutive even natural numbers is 48. Find the greatest of these numbers.
Problem 2 :
The sum of three consecutive odd natural numbers is 69. Find the prime number out of these numbers.
Problem 3 :
The sum of three consecutive numbers is 156. Find the number which is a multiple of 13 out of these numbers.
Problem 4 :
Divide 54 into two parts such that one part is 2/7 of the other.
Problem 5 :
Sum of the digits of a two-digit number is 11. The given number is less than the number obtained by interchanging the digits by 9. Find the number.
Problem 6 :
Two equal sides of a triangle are each 4 m less than three times the third side. Find the dimensions of the triangle, if its perimeter is 55 m.
Problem 7 :
After 12 years, Kanwar shall be 3 times as old as he was 4 years ago. Find his present age.
Problem 8 :
If 1/2 is subtracted from a number and the difference is multiplied by 4, the result is 5. What is the number ?
Problem 9 :
The sum of four consecutive integers is 266. What are the integers ?
Problem 10 :
Find a number whose fifth part increased by 30 is equal to its fourth part decreased by 30.
1) the greatest of these number is 18.
2) the prime number among these three is 23.
3) 52 is the multiple of 13 among these three numbers.
4) 54 is divided into 42 and 12.
5) the required number is 56.
6) the dimensions of the triangle are 9 m, 23 m and 23 m.
7) the Kanwar present age is 12 year.
8) the number is 7/4.
9) the integers are 65, 66, 67, 68.
10) the number is 1200.
Problem 1 :
If 6 = 2x + 4y, what is the value of x + 2y is
(a) 2 (b) 3 (c) 6 (d) 8
Problem 2 :
Solve for y in the equation
and the value of y is.
(a) -1 (b) 7 (c) 1 (d) -1/7
Problem 3 :
Pick up the correct value x for which
(a) x = 0 (b) x = 1 (c) x = 10 (d) None of these
Problem 4 :
The denominator of the fraction exceed the numerator by 5 and if 3 be added to both the fraction becomes 3/4. Find the fraction.
(a) 12/17 (b) 15/17 (c) 12/25 (d) 13/29
Problem 5 :
Three persons Mr. Roy, Mr Paul and Mr. Singh together have $51. Mr Paul has $4 less than Mr Roy and Mr. Singh has got $5 less than Mr.Roy. They have the money as
(a) (20, 16, 15) (b) (15, 20, 16) (c) (25, 11, 15)
Problem 6 :
A number consists of two digits. The digits in the ten's place is 3 times the digit in the unit's place. If 54 is subtracted from the number the digits are reversed. The number is
(a) 39 (b) 92 (c) 93 (d) 94
Problem 7 :
The number consists of two digits, the digit in the ten's place is twice the digit in the unit's place. If 18 be subtracted from the number the digits are reversed. Find the number
(a) 42 (b) 24 (c) 33 (d) 61
Problem 8 :
Solving 4x⋅2y = 128 and 33x+2y = 9xy, we get the following roots.
(a) 7/4, 7/2 (b) 2, 3 (c) 1, 2 (d) 1, 3
Problem 9 :
Solving 9x = 3y and 5x+y+1 = 25xy, we get the following roots.
(a) 1, 2 (b) 0, 1 (c) 0, 3 (d) 1, 3
Problem 10 :
Solving 9x + 3y - 4z = 3, x + y - z = 0 and 2x - 5y - 4z = -20 the following roots obtained.
(a) 2, 3, 4 (b) 1, 3, 4 (c) 1, 2, 3 (d) None
Problem 11 :
One machine can seal 360 packages per hour, and an older machine can seal 140 packages per hour. How many minutes will the two machines working together take to seal a total of 700 packages?
(a) 48 (b) 72 (c) 84 (d) 90
Problem 12 :
The age of a person is 8 years more than thrice the age of the sum of his two grandsons who were twins. After 8 years his age will be 10 years more then twice the sum of the ages of his grandsons. Then the age of the person when twins born is
(a) 86 years (b) 73 years (c) 68 years (d) 63 years
1) The value of x + 2y is 3.
2) y = -1/7
3) x = 10
4) 12/17
5) (20, 16, 15).
6) the required two digit number is 93.
7) the required two digit number is 42.
8) the required roots are 2 and 3.
9) the solution is (1, 2).
10) the solution is (1, 2, 3).
11) 84 minutes is required to seal 700 packages.
12) the age of the person is 73 years.
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM