Problem 1 :
Which term of the AP
3/√7, 4/√7, 5/√7, ............ is 17/√7 ?
Problem 2 :
Divide 69 into three parts which are in A.P and are such that the product of the first two parts is 483.
Problem 3 :
Insert 4 arithmetic means between 4 and 324
Problem 4 :
If the pth term of an A.P is q and qth term is p the value of the rth term is
(a) p - q - r (b) p + q - r (c) p + q + r (d) None
Problem 5 :
The sum of a series in A.P is 72 the first term is 17 and the common difference -2, the number of terms is
(a) 6 (b) 12 (c) 6 or 12 (d) None
Problem 6 :
The sum of all natural numbers between 500 and 1000, which are divisible by 13 is
(a) 28400 (b) 28405 (c) 28410 (d) None
Problem 7 :
If the 10th term of an A.P. is twice the 4th term, and the 23rd term is 'k' times the 8th term, then the value of 'k' is
(a) 2.5 (b) 3 (c) 3.5 (d) 4
Problem 8 :
The sum of the A.M. and G.M. of two positive numbers is equal to the difference between the numbers. The numbers are in the ratio.
(a) 1 : 3 (b) 1 : 6 (c) 9 : 1 (d) 1 : 12
1) 15th term of the arithmetic series is 17/√7.
2) The required terms are 21, 23 and 25.
3) 68, 132, 196, 260
4) tr = q + p - r, option b.
5) n = 6 and n = 12
6) 28405
7) k = 2.5
8) 9 : 1
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM