Problem 1 :
Which term of the AP
3/√7, 4/√7, 5/√7, ............ is 17/√7 ?
Problem 2 :
Divide 69 into three parts which are in A.P and are such that the product of the first two parts is 483.
Problem 3 :
Insert 4 arithmetic means between 4 and 324.
Problem 4 :
If the pth term of an A.P is q and qth term is p the value of the rth term is
(a) p - q - r (b) p + q - r (c) p + q + r (d) None
Problem 5 :
The sum of a series in A.P is 72 the first term is 17 and the common difference -2, the number of terms is
(a) 6 (b) 12 (c) 6 or 12 (d) None
Problem 6 :
The sum of all natural numbers between 500 and 1000, which are divisible by 13 is
(a) 28400 (b) 28405 (c) 28410 (d) None
Problem 7 :
If the 10th term of an A.P. is twice the 4th term, and the 23rd term is 'k' times the 8th term, then the value of 'k' is
(a) 2.5 (b) 3 (c) 3.5 (d) 4
Problem 8 :
t12 of the series -128, 64, -32, ................ is
(a) -1/16 (b) 16 (c) 1/16 (d) None
Problem 9 :
The last term of the series
x2, x, 1.................. to 31 terms is
(a) x28 (b) 1/x (c) 1/x28 (d) None
Problem 10 :
The sum of the series
243, 81, 27, ............. to 8 terms.
(a) 36 (b) 36 13/30 (c) 36 1/9 (d) None
Problem 11 :
The second terms of a G.P is 24 and the fifth term is 81. The series is
(a) 16, 36, 24, 54,.... (b) 24, 36, 53, .......
(c) 16, 24, 36, 54, ........ (d) None
Problem 12 :
The sum of n terms of the series 4 + 44 + 444 + .......... is
(a) (4/9)[(10/9) (10n - 1) - n] (b) (10/9)(10n - 1) - n
(c) 4/9(10n - 1) - n (d) None
Problem 13 :
The sum of first 20 terms of a G.P is 244 times the sum of the first 10 terms. The common ratio is
(a) ±√3 (b) ±3 (c) √3 (d) None
Problem 14 :
The product of 3 numbers in GP is 729 and the sum of squares is 819, the numbers are
(a) 9, 3, 27 (b) 27, 3, 9 (c) 3, 9, 27 (d) None
Problem 15 :
Four geometric means between 4 and 972 are
(a) 12, 36, 108, 324 (b) 12, 24, 108, 320
(c) 10, 36, 108, 320 (d) None
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM