Use the first derivative to find the slope of the tangent line to the given curve at the given point:
Problem 1 :
y = 2x2 + 6 at (-1, 8)
Problem 2 :
y = -x2 + 2x - 3 at (2, 3)
Problem 3 :
y = 4 - 3x3 at (1, 1)
Problem 4 :
Problem 5 :
Tangent lines are drawn to the parabola
y = x2 at (2, 4) and (-1/8, 1/64)
Prove the tangents are perpendicular.
Problem 6 :
Find a point on the parabola
y = -x2 +3x + 4
where the slope of the tangent line is 5.
Problem 7 :
Find the slope of the tangent line to the graph of
3x2 + 5 lny = 12 at (2, 1) is
A) -12/5 B) 12/5 C) 5/12 D) 12 E) -7
Problem 8 :
1) 2
2) 0
3) -5
4) 8
5) So, the tangents drawn at the points (2, 4) and (-1/8, 1/64) for the parabola, they are perpendicular.
6) the required point is (-1, 0).
7) the required slope is -12/5. Option A.
8) the required value of y is 58/7, option C.
Sep 22, 23 08:41 AM
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Sep 22, 23 06:09 AM