Problem 1 :
6(cos 30° + i sin 30°)
Solution:
By comparing the given polar form to the general equation of polar form r(cos θ + i sin θ), we get r = 6 and θ = 30°.
Rectangular form of a complex number is x + iy
x = r cosθ and y = r sinθ
Finding real part:
x = 6 cos 30°
= 6 × √3/2
x = 3√3
Hence the real part of the complex number is 3√3.
Finding imaginary part:
y = 6 sin 30°
= 6 × (1/2)
y = 3
So, the rectangular form of the complex number is
3√3 + 3i
Write each complex number in rectangular form. If necessary, round to the nearest tenth.
Problem 2 :
12(cos 60° + i sin 60°)
Solution:
Rectangular form of a complex number is x + iy
x + iy = 12 cos 60° + i12 sin 60°
x = r cosθ and y = r sinθ
r = 12 and θ = 60°
Finding real part:
x = 12 cos 60°
= 12 × (1/2)
x = 6
Hence the real part of the complex number is 6.
Finding imaginary part:
y = 12 sin 60°
= 12 × (√3/2)
y = 6√3
So, the rectangular form of the complex number is
6 + 6√3i
Problem 3 :
4(cos 240° + i sin 240°)
Solution:
Rectangular form of a complex number is x + iy
x + iy = 4cos 240° + i4sin 240°
x = r cosθ and y = r sinθ
r = 4 and θ = 240°
Finding real part:
x = 4 cos 240°
x = 4 cos (180° + 60°)
Since 240° lies in third quadratic, we have to put positive sign only for tan θ and its cot θ only. Here we have to put negative sign.
x = 4 cos 60°
= -4 × (1/2)
x = -2
Hence the real part of the complex number is -2.
Finding imaginary part:
y = 4 sin 240°
y = 4 sin (180° + 60°)
y = -4 sin 60°
= -4 × (√3/2)
y = -2√3
So, the rectangular form of the complex number is
-2 - 2√3i
Problem 4 :
10(cos 210° + i sin 210°)
Solution:
Rectangular form of a complex number is x + iy
x + iy = 10 cos 210° + i10 sin 210°
x = r cosθ and y = r sinθ
r = 10 and θ = 210°
Finding real part:
x = 10 cos 210°
x = 10 cos (180° + 30°)
Since 210° lies in third quadratic, we have to put positive sign only for tan θ and its cot θ only. Here we have to put negative sign.
= -10 cos 30°
= -10 × (√3/2)
x = -5√3
Hence the real part of the complex number is -5√3.
Finding imaginary part:
y = 10 sin 210°
y = -10 sin (180° + 30°)
= -10 sin 30°
= -10 × (1/2)
y = -5
So, the rectangular form of the complex number is
-5√3 - 5i
Problem 5 :
Solution:
Rectangular form of a complex number is x + iy
Finding real part:
Since 315° lies in fourth quadratic, we have to put positive sign only for cos θ and its reciprocal sec θ only.
Hence, the real part of the complex number is 4√2.
Finding imaginary part:
So, the rectangular form of the complex number is
4√2 - 4√2i
Problem 6 :
Solution:
Rectangular form of a complex number is x + iy
Finding real part:
Since 150° lies in second quadratic, we have to put positive sign only for sin θ and its reciprocal cosec θ only.
Hence, the real part of the complex number is -2√3.
Finding imaginary part:
So, the rectangular form of the complex number is
-2√3 + 2i
Problem 7 :
Solution:
Rectangular form of a complex number is x + iy
Finding real part:
Since 90° lies in the first quadrant, we have to put positive sign for all trigonometric ratios.
x = 5 cos 90°
x = 5(0)
x = 0
Hence, the real part of the complex number is 0.
Finding imaginary part:
y = 5 sin 90°
y = 5(1)
y = 5
So, the rectangular form of the complex number is
0 + 5i
Problem 8 :
Solution:
Rectangular form of a complex number is x + iy
Finding real part:
Since 270° lies in third quadratic, we have to put positive sign only for tan θ and its reciprocal cot θ only. Here we have to put negative sign.
Hence, the real part of the complex number is 0.
Finding imaginary part:
So, the rectangular form of the complex number is
0 - 7i
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM