Problem 1 :
Find the simple interest rate (to the nearest per cent) which will allow €2500 to earn €675 interest in 3 years.
Problem 2 :
What sum of money would you have to invest for 5 years at 11% simple interest to produce interest at €3080?
Problem 3 :
For how many years would $8000 have to be invested at 11 1/2% simple interest to produce €5520 interest?
Problem 4 :
What simple interest rate would allow €6000 to grow to an amount €14550 in 10 years?
Problem 5 :
What simple interest would $8000 earn in 3 months if the rate of interest is 11 1/4 % pa?
Problem 6 :
A building society pays interest daily. If an amount of $1564 were invested at 5.5% pa, how much simple interest would be earned in:
i. 1 day? ii. 3 days? iii. 29 days?
1) R = 9%
2) P = €5600
3) T = 6 years
4) r = 14.25% pa
5) SI=$225
6) i) SI = $0.24 ii) SI = $0.71 iii) SI = $6.83
Find the simple interest charged when :
Problem 1 :
$5000 is borrowed for 1 year at 12% per annum simple interest. Solution
Problem 2 :
$2500 is borrowed for 2 years at 8% per annum simple interest. Solution
Problem 3 :
$40000 is borrowed for 5 years at 11% per annum simple interest. Solution
Problem 4 :
$250000 is borrowed for 9 months at 20% per annum simple interest. Solution
Find the total amount needed to repay a loan of :
Problem 5 :
$2400 borrowed for 3 years at 10% per annum simple interest.
Problem 6 :
$8000 borrowed for 7 years at 12% per annum simple interest.
Problem 7 :
$7500 borrowed for 2 1/2 years at 8% per annum simple interest.
Problem 8 :
$23000 borrowed for 4 months at 15% per annum simple interest.
Problem 9 :
Kyle borrows $25000 at 6% p.a. Simple interest for 4 years.
(a) Find the total amount needed to repay the loan.
(b) Calculate the monthly repayment required to pay this loan off in 48 equal instalments.
1) I = 600 2) I = 400 3) $22000 4) $37500 5) I = $720, P = $3120 |
6) I = $6720, P = $14720 7) I = $1500, P = $9000 8) I = $1150, P = $24150 9) a) I = 6000, P = 31000 b) $645.83 |
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM