WORD PROBLEMS INVOLVING PERCENTAGE

Always the original quantity can be considered as 100%.

Problem 1 :

A shop sells 200 chocolate, Vannila and strawberry ice creams. 45% of the ice creams sold are Vannila, and 30% are Strawberry. How many chocolate ice creams are sold ?

Solution :

Let us consider the given quantity as 100%.

200 = 100%

45% of ice creams are Vannila, 30% of ice creams are Strawberry.

Percentage of chocolate ice creams sold = 100 - (45 + 30)

= 100 - 75

= 25%

Number of chocolate ice creams = 25% of 200

= 0.25(200)

= 50

Problem 2 :

An animal park has lions, tigers and Zebras. 20% of the animals are lions and half of the animals are Zebras. If there are 120 animals at the park how many tigers are there ?

Solution :

Total number of animals = 120 = 100%.

20% of them are lions.

Half of them = 50% of the animals are Zebra.

Percentage of animals which are tiger = 100 - (20 + 50)

= 100 - 70

= 30%

30% of the animals are tigers.

Number of tigers = 30% of 120

= 0.30(120)

= 36

Problem 3 :

LA Galaxy have won 36% of their soccer matches, if they have played 50 matches, how many have they won ?

Solution :

Total number of matches they played = 50

Number of matches they won = 36% of the matches

= 36% of 50

= 0.36 (50)

= 18

So, they won 18 matches.

Problem 4 :

A car can travel 400 miles on a full tank of petrol. A more efficient car can travel 30% further. How many miles can it travel on a tank ?

Solution :

Distance covered by the car using full tank of petrol = 400 miles

400 miles = 100% of the distance

100 + 30 = 130% of 400

= 1.30 (400)

= 520 miles

So the efficient car can cover 520 miles.

Problem 5 :

In a fruit survey, 60 children choose their favourite  fruit out of the apples, bananas and watermelon. 30% of chose apples, 25% chose bananas. How many children chose watermelon ?

Solution :

Total number of children = 60 = 100%

Percentage of children who choose watermelon

= 100 - (30 + 25)

= 100 - 55

= 45%

Number of children who choose watermelon = 45% of 60

= 0.45(60)

= 27

So, 27 children choose watermelon.

Problem 6 :

In a traffic survey of 200 vehicles, bikes, buses and cars were recorded. 3/4 of the vehicles were cars and 17% were buses. How many bikes were there ?

Solution :

Total number of vehicles participated in the survey = 200

100% = 200 chocolates

3/4 of the vehicles = 75% of vehicles are cars.

Percentage of buses = 17%

Percentage of vehicles which are bikes = 100 - (75 + 17)

= 100 - 92

= 8%

8% of bikes are there.

Number of bikes = 8% of 200

= 0.08(200)

= 16

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