Problem 1 :
Let f(x) = 3 sec 2x, which of the following is the vertical asymptote on the graph f ?
a) x = π b) x = 3π/2 c) x = π/4 d) x = 0
Problem 2 :
Let g(x) = 4 - 2 csc (πx), which of the following is the vertical asymptote on the graph g ?
a) x = π/2 b) x = π c) x = 1/2 d) x = 1
Problem 3 :
Let k(x) = -5 cot (2πx), which of the following is the vertical asymptote on the graph k ?
a) x = 1/4 b) x = 1/2 c) x = π/2 d) x = 2π
Problem 4 :
In order to graph y = (1/2) tan 2x, an interval containing one period is found by solving - π/2 < 2x < π/2.
An interval containing one period is two consecutive asymptotes occur at x = and x = .
Problem 5 :
An interval containing one period of y = tan (x - π/2) is at x = . Thus, two consecutive asymptotes occur and x = and x =
1) x = π/4, 3π/4, ......
Accordingly the given option x = π/4 is the vertical asymptote for the function f(x).
2) x = 0, 1, 2 , ......
Accordingly the given option x = 1 is the vertical asymptote for the function g(x).
3) Accordingly the given option x = 1/2 is the vertical asymptote for the function k(x).
4) So, consecutive vertical asymptotes are appearing at x = -3π/4 and x = π/4.
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM