Union of two sets :
The union of two sets contains all the elements contained in either set (or both sets).
The union is notated A ⋃ B.
Intersection of two sets :
The intersection of two sets contains only the elements that are in both sets.
The intersection is notated A ⋂ B.
Complement of a set :
The complement of a set is the set that includes all the elements of the universal set that are not present in the given set.
The complement of any set is represented as A', B', C' etc.
Problem 1 :
If A is the set of all factors of 36 and B is the set of all factors of 63, find :
a) A ∩ B
b) A U B
Solution :
Given, A is the set of all factors of 36
So, set A = {1, 2, 3, 4, 6, 9, 12, 18, 36}
B is the set of all factors of 63.
So, set B = {1, 3, 7, 9, 21, 63}
a)
A ∩ B = {1, 3, 9}
b)
{1, 2, 3, 4, 6, 7, 9, 12, 18, 21, 36, 63}
Problem 2 :
If X = {A, B, D, M, N, P, R, T, Z} and Y = {B, C, M, T, W, Z}, find :
a) X ∩ Y
b) X U Y
Solution :
Given, X = {A, B, D, M, N, P, R, T, Z} and Y = {B, C, M, T, W, Z}
a) X ∩ Y = {B, M, T, Z}
b) X U Y = {A, B, C, D, M, N, P, R, T, W, Z}
Problem 3 :
If U = {x │ x ≤ 30, x Z+},
A = {factors of 30} and B = {prime numbers ≤ 30}
a) Find :
(i) n(A) (ii) n(B) |
(iii) n(A ∩ B) (iv) n(A U B) |
b) Use a to verify that n(A U B) = n(A) + n(B) - n(A ∩ B)
Solution :
Given, A = {1, 2, 3, 5, 6, 10, 15, 30}
B = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29}
a)
(i) n(A) = 8 (ii) n(B) = 10 |
(iii) n(A ∩ B) = 3 (iv) n(A U B) = 15 |
(b) n(A U B) = n(A) + n(B) - n(A ∩ B)
15 = 8 + 10 - 3
15 = 18 - 3
15 = 15
Hence, it is verified.
Problem 4 :
(a) Use the Venn diagram given to show that :
n(A U B) = n(A) + n(B) - n(A ∩ B)
Note :
(a) Means that there are a elements in this region,
so n(A) = a + b.
(b) Suppose
A and B are disjoint events.
Explain why n(A U B) = n(A) + n(B).
Solution :
a) From Venn diagram,
n(A) = a + b
n(B) = b + c
n(A ∩ B) = b
n(A U B) = a + b + c ---- > (1)
n(A U B) = n(A) + n(B) - n(A ∩ B)
n(A U B) = (a + b) + (b + c) - b
n(A U B) = a + b + c ---- > (2)
(1) = (2)
Hence, it is verified.
(b) A and B are disjoint sets.
n(A ∩ B) = Ø
n(A U B) = n(A) + n(B) - n(A ∩ B)
n(A U B) = n(A) + n(B) - Ø
n(A U B) = n(A) + n(B)
Problem 5 :
Simplify :
a) X ∩ Y for X = {1, 3, 5, 7} and Y = {2, 4, 6, 8}
b) A U A’ for any set A Є U.
c) A ∩ A’ for any set A Є U.
Solution :
a) Given X = {1, 3, 5, 7} and Y = {2, 4, 6, 8}
X ∩ Y = Ø
b) Let U = {1, 2, 3, 4, 5}
A = {1, 2, 3}
A’ = {4, 5}
A U A’ = {1, 2, 3, 4, 5}
c) Let U = {1, 2, 3, 4, 5}
A = {1, 2, 3}
A’ = {4, 5}
A ∩ A’ = Ø
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM