To translate words to algebraic equations or expressions, we should know about what are words to be used to represent algebraic operations.
For addition (+) :
Sum, plus, more than, added to,.........
For subtraction (-) :
Difference, less than, reduced, subtracted from ...................
For multiplication (x) :
Times, product, multiplied by,...........
For division (/) :
Divided by, quotient, ............
Problem 1 :
Write each verbal phrase as an algebraic expression.
1) the sum of 8 and t
2) the quotient of g and 15
3) the product of 5 and b
4) the difference of 32 and x
Solution :
1) Sum = +
Required expression : 8 + t
2) Quotient = /
Required expression : g/15
3) Product = x
Required expression : 5 x b
4) Difference = -
Required expression : 32 - x
Problems 2 :
Questions 5) Eight more than x 6) Six less than p 7) 14 less than f 8) p more than 10 9) 3 more runs than Pirates scored 10) 12 less than some number |
Answers 8 + x p - 6 f - 14 p + 10 x + 3 x - 12 |
Translate the verbal phrase to algebraic equations.
Problem 3 :
Arthur is 8 years younger than Janet
Solution :
Let A be Arthur's age. Janet's age be J.
Arthur's age is 8 less than Janet's age. Because Janet is elder.
A = J - 8
Problem 4 :
Kelly’s test score is 6 points higher than Mike’s
Solution :
Let K be Kell's test score. M be Mike's test score.
K = M + 6
Problem 5 :
5 more than a number is 6.
Solution :
Let x be the unknown.
More than = +
5 + x = 6
Problem 6 :
The product of 7 and b is equal to 63.
Solution :
Product of = x
7 x b = 63
Problem 7 :
The sum of r and 45 is 79.
Solution :
Sum of = +
r + 45 = 79
Problem 8 :
The quotient of x and 7 is equal to 13.
Solution :
Quotient = /
x/7 = 13
Problem 9 :
In a cross-country race you run at a steady rate of 7 minutes per mile. After 21 minutes, you finish in fourth place. How long is the race?
Solution :
The time taken to cover 1 mile = 7 minutes
Total time taken to finish the race = 21 minutes
Duration of race time = 21/7
= 3 minutes
Problem 10 :
For a science project, you record the high temperature each day. The high temperature on Day 1 was 6° less than on Day 4 and 4° less than on Day 10. The high temperature on Day 10 was 62°F. What was the high temperature on Day 1?
Solution :
Temperature on Day 10 = 62°F
Temperature on Day 4 = 62 - 4
= 58°F
Temperature on Day 1 = 58 - 6
= 52°F
So, the temperature on Day 1 is 52°F.
Problem 11 :
Students and faculty raised $6042 for band uniforms. The faculty raised $1780. Write an equation you can use to find the amount a raised by the students.
Solution :
Total amount raised = 6042
Amount raised by faculty = 1780
Amount raised by students = x
x + 1780 = 6042
x = 6042 - 1780
x = 4262
So, the required amount raised by the students is $4262.
Problem 12 :
Together you and a friend have $52. Your friend has $28. Write an equation you can use to find how much money you have.
Solution :
The amount you have = x
The amount your friend have = 28
Total money = 52
x + 28 = 52
x = 52 - 28
x = 24
So, the amount you have is $24.
Problem 12 :
You hit a golf ball 90 yards. It travels three-fourths of the distance to the hole. Write an equation you can use to find the distance d from the tee to the hole.
Solution :
Total distance from tee to the target is d yards.
3/4 of d = 90
(3/4)d = 90
3d/4 = 90
3d = 90(4)
3d = 360
d = 360/3
d = 120 yards.
Problem 13 :
Which expression is equivalent to 8(x + 3)?
a) 8x + 3 b) 8x + 24 c) 8x + 11 d) x + 24
Solution :
Using distributive property, multiplying 8 by x + 3, we get
= 8x + 8(3)
= 8x + 24
So, option b is correct.
Problem 14 :
Evaluate the expression when a = 7
a) 6 + a b) a − 4 c) 4a d) 35/a
Solution :
a) 6 + a When a = 7 = 6 + 7 = 13 |
b) a − 4 When a = 7 = 7 - 4 = 3 |
c) 4a When a = 7 = 4(7) = 28 |
d) 35/a When a = 7 = 35/7 = 5 |
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM