If one quantity is being divided in the ratio a : b, then the first part and second parts can be considered as ax and bx respectively.
By adding those two parts, we will be getting the original quantity.
Using the concepts proportions and cross multiplication rule, we can solve it further and get the value of the variable involved in the problem.
Problem 1 :
The ratio of boys and girls in the school is 7 : 9, when 22 new boys are joined in this school then the ratio becomes 9 : 10. How many girls in this school?
Solution :
The ratio = 7x
: 9x
Number of boys are joined in this school = 22
The ratio = 9 : 10
7x + 22/9x = 9/10
By using cross multiplication. We get
70x + 220 = 81x
By combining like terms
220 = 81x – 70x
220 = 11x
220/11 = x
20 = x
Number of girls = 9x
= 9(20)
= 180
So,180 girls in this school.
Problem 2 :
If two numbers are in the ratio 11 : 13 and their difference is 8, find the numbers.
Solution :
Let the numbers be 11x and 13x
Difference between the numbers = 8
3x – 11x = 8
2x = 8
x = 4
Value of 11x = 11(4) = 44
Value of 13x = 13(4) = 52
So, the numbers are 44, 52.
Problem 3 :
The length and breadth of the rectangle are in the ratio 9 : 7. Find the perimeter of the rectangles if its breadth is 378 cm.
Solution :
Length of the rectangle = 9x and breadth of the rectangle 7x.
Given, breadth of the rectangle = 378 cm
7x = 378
x = 378/7
x = 54 cm
Length of the rectangle = 9x = 9(54)= 486 cm
Perimeter of the rectangle = 2(l + b)
= 2(486 + 378)
= 2 × 864
= 1728
So, the perimeter of the rectangle is1728 cm.
Problem 4 :
Find the measures of the angles of a triangle if the ratio of their measures is 4 : 12 : 29.
Solution :
Let x be the measures of the angles of a triangle.
The ratio of their measures = 4 : 12 : 29.
x = 4
4x = 4 × 4 = 16
12x = 12 × 4 = 48
29x = 29 × 4 = 116
So, the measures of the angles of a triangle is 16, 48, 116.
Problem 5 :
The perimeter of a square is 26 cm while the area of another square is 121 cm2. Find the ratio of their lengths.
Solution :
Given, the perimeter of a square = 26 cm
Area of a square = 121 cm2
Perimeter of a square = 4 x side
26 = 4 x side
26/4 = side
s = 6.5 cm
Area of a square = side x side
121 = side2
√121= side1
side1 = 11
So, the ratio of their lengths is 6.5, 11.
Problem 6 :
The ratio of boys to girls is 3 to 2. If there are 12 boys, how many girls are there?
Solution :
Ratio between boys to girls = 3 : 2
Number of boys = 3x and number of girls = 2x
3x = 12 (Given)
x = 12/3
x = 4
Number of girls = 2(4) ==> 8
Problem 7 :
It takes one Super Giant Pizza to feed 3 people. If you invite 36 people, how many pizzas will you need?
Solution :
1 pizza will be served for 3 people.
3x = 36
x = 36/3
x = 12
Number of pizzas to be ordered = 12 pizzas
Problem 8 :
At a recent party, it cost $9.50 for refreshments for 10 guests. At this rate, how much would it cost to have refreshments for 80 guests?
Solution :
Cost spent for 10 guests = $9.50
Cost spent for 80 guests = 9.50 x 8
= $76
Amount spent for 80 guests is $76.
Problem 9 :
A car can travel 240 km in 15 litres of petrol. How much distance will it travel in 25 litres of petrol?
Solution :
15 liters of petrol will cover the distance 240 km
Let x be the distance covered using 25 liters of petrol.
15 : 240 = 25 : x
15x = 25(240)
x = 25(240) / 15
x = 400
So, the required distance covered is 400 km.
Problem 10 :
The yield of wheat from 8 hectares of land is 360 quintals. Find the number of hectares of land required for a yield of 540 quintals?
Solution :
8 hectares of land will yield 360 quintals
Let x be the land required in hectares.
8 : 360 = x : 540
8/360 = x/540
8(540) = 360x
x = 8(540)/360
x = 8(1.5)
x = 12
So, the required quantity of land is 12 hectares.
Problem 11 :
The earth rotates 360o about its axis in about 24 hours. By how much degree will it rotate in 2 hours?
Solution :
Ratio between angle measure to number of hours.
360 : 24
Let x be the required degree in 2 hours.
360 : 24 = x : 2
360/24 = x/2
360(2) = 24x
x = 720/24
x = 30
So, the required degree in 2 hours is 30o
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