SOLVING RATIO WORD PROBLEMS

If one quantity is being divided in the ratio a : b, then the first part and second parts can be considered as ax and bx respectively.

By adding those two parts, we will be getting the original quantity.

Using the concepts proportions and cross multiplication rule, we can solve it further and get the value of the variable involved in the problem.

Problem 1 :

Two numbers are in the ratio of 3 : 5. If 9 is substracted from each, the ratio becomes 12 : 23. Find the greater number?

Solution :

Let the numbers be 3x : 5x

9 is substracted from 3x and 5x.

(3x – 9)/(5x – 9) = 12/23

Doing cross multiplication. We get

23(3x – 9) = 12(5x – 9)

69x – 207 = 60x – 108

By combining the like terms

69x – 60x = 207 – 108

9x = 99

x = 99/9

x = 11

So, the greater number is 5x = 5(11) = 55.

Problem 2 :

When 7 is added to the numerator and denominator of the fraction, then the new ratio of becomes 13 : 19, what is the original ratio?

Solution :

Let x/y be the required fraction.

7 is added to the numerator and denominator of the fraction.

(x + 7) /(y + 7) = 13/19

19(x + 7) = 13(y +7)

19x + 133 = 13y + 91

So, the original ratio cannot be determined.

Problem 3 :

The ratio of age of krish and her mother is 5 : 12 and difference of their ages is 21. What will be the ratio of their ages after 3 years?

Solution :

Let 5x be krish's age and 12x be her mother's age.

Difference of their ages = 21

12x - 5x = 21

7x = 21

x = 21/7

x = 3

Age of krish = 5x = 5(3) = 15

Mother age = 12x = 12(3) = 36

After 3 years, Krish's age = 15 + 3 ==> 18

After 3 years, Mother's age = 36 + 3 ==> 39

So, the ratio is 18 : 39.

HCF of (18 : 39) is 3.

Dividing both parts by 3.

= 6 : 13

So, the ratio of their ages after 3 years = 6 : 13.

Problem 4 :

Ratio of A and B in the ratio of 5 : 8. After 6 years, the ratio of ages of  A and B will be in the ratio of 17 : 26. Find the present age of B.

Solution :

A and B in the ratio of 5 : 8.

Those two quantities will be 5x and 8x.

After 6 years the ratio of ages of A and B = 17 : 26

17/26 = (5x + 6)/(8x + 6)

By using cross multiplication. We get

17(8x + 6) = 26 (5x + 6)

136x + 102 = 130x + 156

By combining like terms

136x – 130x = 156 – 102

6x = 54

x = 54/6

x = 9

So, the present age of B = 8x = 8(9)

= 72 years

Problem 5 :

The ratio of the length of a vertical pole and its shadow on the ground is 7 : 2. Find the length of the pole, if the length of the shadow is 2.4 m.

Solution :

Let x be the length of the pole.

Given the length of the shadow is 2.4 m.

The length of

vertical pole and shadow = 7 : 2

x/(2.4) = 7/2

By using cross multiplication. We get

2x = 16.8

x = 16.8/2

x = 8.4 m

So, the length of the pole is 8.4 m.

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