If one quantity is being divided in the ratio a : b, then the first part and second parts can be considered as ax and bx respectively.
By adding those two parts, we will be getting the original quantity.
Using the concepts proportions and cross multiplication rule, we can solve it further and get the value of the variable involved in the problem.
Problem 1 :
Two numbers are in the ratio of 3 : 5. If 9 is substracted from each, the ratio becomes 12 : 23. Find the greater number?
Solution :
Let the numbers be 3x : 5x
9 is substracted from 3x and 5x.
(3x – 9)/(5x – 9) = 12/23
Doing cross multiplication. We get
23(3x – 9) = 12(5x – 9)
69x – 207 = 60x – 108
By combining the like terms
69x – 60x = 207 – 108
9x = 99
x = 99/9
x = 11
So, the greater number is 5x = 5(11) = 55.
Problem 2 :
When 7 is added to the numerator and denominator of the fraction, then the new ratio of becomes 13 : 19, what is the original ratio?
Solution :
Let x/y be the required fraction.
7 is added to the numerator and denominator of the fraction.
(x + 7) /(y + 7) = 13/19
19(x + 7) = 13(y +7)
19x + 133 = 13y + 91
So, the original ratio cannot be determined.
Problem 3 :
The ratio of age of krish and her mother is 5 : 12 and difference of their ages is 21. What will be the ratio of their ages after 3 years?
Solution :
Let 5x be krish's age and 12x be her mother's age.
Difference of their ages = 21
12x - 5x = 21
7x = 21
x = 21/7
x = 3
Age of krish = 5x = 5(3) = 15
Mother age = 12x = 12(3) = 36
After 3 years, Krish's age = 15 + 3 ==> 18
After 3 years, Mother's age = 36 + 3 ==> 39
So, the ratio is 18 : 39.
HCF of (18 : 39) is 3.
Dividing both parts by 3.
= 6 : 13
So, the ratio of their ages after 3 years = 6 : 13.
Problem 4 :
Ratio of A and B in the ratio of 5 : 8. After 6 years, the ratio of ages of A and B will be in the ratio of 17 : 26. Find the present age of B.
Solution :
A and B in the
ratio of 5 : 8.
Those two quantities will be 5x and 8x.
After 6 years the ratio of ages of A and B = 17 : 26
17/26 = (5x + 6)/(8x + 6)
By using cross multiplication. We get
17(8x + 6) = 26 (5x + 6)
136x + 102 = 130x + 156
By combining like terms
136x – 130x = 156 – 102
6x = 54
x = 54/6
x = 9
So, the present age of B = 8x = 8(9)
= 72 years
Problem 5 :
The ratio of the length of a vertical pole and its shadow on the ground is 7 : 2. Find the length of the pole, if the length of the shadow is 2.4 m.
Solution :
Let x be the length of the pole.
Given the length of the shadow is 2.4 m.
The length of
vertical pole and shadow = 7 : 2
x/(2.4) = 7/2
By using cross multiplication. We get
2x = 16.8
x = 16.8/2
x = 8.4 m
So, the length of the pole is 8.4 m.
Problem 6 :
If the cost of 14 m cloth is $1890, find the cost of 6 m cloth.
Solution :
Cost of 14 m cloth = 1890
Let x be the cost of 6 m cloth.
Ratio between quantity of cloth to its price = 14 : 1890
14 : 1890 = 6 : x
14/1890 = 6/x
14x = 6(1890)
x = 6(1890)/14
x = 810
So, cost of 6 m cloth is $810.
Problem 7 :
The value of m, if 3, 18, m, 42 are in proportion is
a) 6 b) 54 c) 7 d) none
Solution :
3, 18, m, 42
3 : 18 = m : 42
3/18 = m/42
3(42) = m(18)
m = 3(42) / 18
m = 7
So, option c is correct.
Problem 8 :
If 20% of x = 30% of y, then x : y = ?
Solution :
20% of x = 30% of y
0.20x = 0.30y
x / y = 0.30 / 0.20
x / y = 3/2
x : y = 3 : 2
So, the required ratio is 3 : 2.
Problem 9 :
Two numbers are in the ratio fo 8 : 3 and their sum is 242. Find the difference between two numbers.
Solution :
Let the numbers be 8x and 3x.
8x + 3x = 242
11x = 242
x = 242/11
x = 22
Applying the value of x, we get
8(11) ==> 88
3(11) ==> 33
Their difference = 88 - 33
= 55
Problem 10 :
Present age of Rani and Kami are in the ratio of 5 : 6 respectively. 7 years hence this ratio will become 6 : 7 respectively. What is Rani's present age ?
Solution :
Ratio between the present age = 5 : 6
After 7 years. The new ages will be 5x + 7 and 6x + 7
5x + 7 : 6x + 7 = 6 : 7
7(5x + 7) = 6(6x +7)
35x + 49 = 36x + 42
36x - 35x = 49 - 42
x = 7
Rani's present age = 5(7) ==> 35 years
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM