Find the extraneous solution for the radical equations given below.
1) √(x + 4) = x - 2 Solution
2) √(10x + 9) = x + 3 Solution
3) √(2x + 5) = √(x + 7) Solution
4) √(x + 6) – 2 = √(x – 2) Solution
5) x+1 = √(7x+15) Solution
6) √(x + 2) + 1= √(3 – x) Solution
7) √(10 - x) = x + 2 Solution
1) 0 is solution, 5 is extraneous
2) 0 and 4 are solutions. No extraneous solution
3) 2 is a solution. No extraneous solution
4) 3 is a solution. No extraneous solution.
5) 7 is a solution. -2 is extraneous solution.
6) -1 is solution and 2 is extraneous
7) 1 is solution, -6 is extraneous
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM