Problem 1 :
Solving x3 + 9x2 - x - 9 = 0 we get the following roots
(a) ± 1,-9 (b) ±1, ±9 (c) ±1, 9 (d) None
Problem 2 :
The solution of the cubic equation x3 - 6x2 + 11 x - 6 = 0 is given by the triplet
(a) (-1, 1, -2) (b) (1, 2, 3) (c) (-2, 2, 3) (d) (0, 4, -5)
Problem 3 :
For the given polynomial
x3 - 2x2 - 5x + 6
If 3 is one of the zeroes, find the others.
Problem 4 :
Is x = 4 a root of the equation x3 − 6x2 + 9x + 1 = 0?.
Problem 5 :
Find a polynomial function P(x) of degree 3 with real coefficients that satisfies the given conditions.
Zeros of -3, -1, and 4; P(2) = 5
1) x = -1, 1 and 9.
2) x = 1, 2 and 3
3) x = -2, 1 and 3.
4) 4 is not a root of the polynomial.
5) k = -1/6
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM