SOLVE EQUATIONS WITH PARENTHESES

Problem 1 :

(5 ⋅ 60) – 2 = n

Solution :

Using BODMAS, first we simplify the terms inside the parenthesis.

By multiplying 5 and 60 we get,

n = 300 – 2

n = 298

Problem 2 :

2.5 + (4 ÷ 0.1) = b

Solution :

Here we have 4  ÷ 0.1 inside the bracket, by dividing 4 and 0.1 we get,

b = 2.5 +  40

b = 42.5

Problem 3 :

Solution :

Using BODMAS, first we simplify the terms inside the parenthesis.

Converting the mixed fraction to improper fraction, we get

1 1/2 = 3/2

3/2 = 1.5

1/8 = 0.125

By subtracting 1.5 from 0.125  we get,

Problem 4 :

Solution :

Here we have 2  ÷ 1/4.inside the bracket,

1/4 = 0.25

By dividing 2 and 0.25 we get,

Problem 5 :

Solution :

Whenever we want to evaluate an algebraic expression, first we have to do the operations inside parentheses.

Converting the mixed fraction to improper fraction, we get

1 3/4 = 7/4

7/4 = 1.75

By dividing 1.75 to 3  we get,

Problem 6 :

Solution :

Problem 7 :

1.55 – (0.7 ⋅ 2) = r

Solution :

Whenever we want to evaluate an algebraic expression, first we have to do the operations inside parentheses.

By multiplying 0.7 and 2 we get,

r = 1.55 – 1.4

r = 0.15

Problem 8 :

(0.01⋅100) – 1 = w

Solution :

Whenever we want to evaluate an algebraic expression, first we have to do the operations inside parentheses.

By multiplying 0.01 and 100 we get,

w = 1 – 1

w = 0