Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.
If we have power raised to another power, we have to multiply the powers.

If we have numerical values inside the parenthesis,
Simplify the following without using calculator.
Example 1 :
(-32)2/5
Solution :
= (-32)2/5
Decomposing 32, we get
-32 = (-2) ⋅ (-2) ⋅ (-2) ⋅ (-2) ⋅ (-2)
-32 = (-2)5
(-32)2/5 = [(-2)5]2/5
Since we have power raised to another power, we have to multiply the powers.
= (-2)5 ⋅ 2/5
= (-2)2
(-32)2/5 = 4
Example 2 :
(-8)4/3
Solution :
= (-8)4/3
Decomposing -8, we get
-8 = (-2) ⋅ (-2) ⋅ (-2)
-8 = (-2)3
(-8)4/3 = [(-2)3]4/3
= (-2)3
= -8
Example 3 :
(8/27)4/3
Solution :
= (8/27)4/3
Decomposing 8 and 27, we get
|
8 = 2 ⋅ 2 ⋅ 2 8 = 23 |
27 = 3 ⋅ 3 ⋅ 3 27 = 33 |
(8/27)4/3 = [(2/3)3]4/3
= (2/3) 3 ⋅ (4/3)
= (2/3)4
= 16/81
Example 4 :
(125)1/3
Solution :
= (125)1/3
Decomposing 125, we get
125 = 5 ⋅ 5 ⋅ 5 ==> 53
= (53)1/3
= 53 ⋅ (1/3)
= 5
Example 5 :
(8x15)-1/3
Solution :
= (8x15)-1/3
Decomposing 8, we get
8 = 2 ⋅ 2 ⋅ 2 ==> 23
= (23 (x5)3)-1/3
= (2x5)3 ⋅ (-1/3)
= (2x5)-1
=1/(2x5)
Example 6 :
(h6p9/1000m3)-2/3
Solution :
Example 7 :
(64)1/6
Solution :
= (64)1/6
Decomposing 64, we get
64 = 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 2
64 = 26
(64)1/6 = (26)1/6
= 2 (6 ⋅ 1/6)
= 2
Example 8 :
(256)3/4
Solution :
= (256)3/4
Decomposing 256, we get
256 = 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 2
256 = 44
(256)3/4 = (44)3/4
= 43
= 64
Example 8 :
evaluate the expression without using a calculator.
|
a) 641/6 b) 81/3 c) 253/2 d) 813/4 |
e) (−243)1/5 f) (−64)4/3 g) 8−2/3 h) 16−7/4 |
Solution :
a) 641/6
Step 1 :
Writing 64 in expanded form.
64 = 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 2
Step 2 :
Writing the expanded form in exponential form, we get
= 26
Step 3 :
Replacing the exponential form in the question and multiplying the power raised by another power.
641/6 = (26)1/6
= 26 x (1/6)
= 2
b) 81/3
Step 1 :
Writing 8 in expanded form.
8 = 2 ⋅ 2 ⋅ 2
Step 2 :
Writing the expanded form in exponential form, we get
= 23
81/3 = (23)1/3
= 23x(1/3)
= 2
c) 253/2
25 = 5 ⋅ 5
= 52
253/2 = (52)3/2
= 52 x (3/2)
= 53
= 125
d) 813/4
Step 1 :
Writing 81 in expanded form.
81 = 9 ⋅ 9
Step 2 :
Writing the expanded form in exponential form, we get
= 34
813/4 = (92)3/4
= 92 x (3/2)
= 93
= 729
e) (−243)1/5
Step 1 :
Writing 243 in expanded form.
243 = 3 ⋅ 3 ⋅ 3 ⋅ 3 ⋅ 3
Step 2 :
Writing the expanded form in exponential form, we get
= 35
(−243)1/5 = ((-3)5)1/5
= (-3)5 x (1/5)
= -3
f) (−64)4/3
Step 1 :
Writing 64 in expanded form.
64 = 4 ⋅ 4 ⋅ 4
Step 2 :
Writing the expanded form in exponential form, we get
= 43
(−64)4/3 = ((-4)3)4/3
= (-4)3 x (4/3)
= (-4)4
We have negative base and even number as exponent, then the negative sign can be changes as positive.
= 256
g) 8−2/3
8 = 2 ⋅ 2 ⋅ 2 ==> 83
8−2/3 = (83)−2/3
= 8−2
= 1/82
= 1/64
h) 16−7/4
16 = 2 ⋅ 2 ⋅ 2 ⋅ 2 ==> 24
16−7/4 = (24)−7/4
= 2−7
= 1/27
= 1/128
Example 9 :
a) 3(1111/4) + 9(1111/4)
b) 13(83/4) − 4(83/4)
c) 27√6 + 7√150
d) ∜(1296/25)
Solution :
a) 3(1111/4) + 9(1111/4)
Since these two are like terms, we can add them.
= 12(1111/4)
It cannot be simplified further.
b) 13(83/4) − 4(83/4)
= 9(83/4)
= 9((23)3/4)
= 9(29/4)
c) 27√6 + 7√150
√150 = √(5 ⋅ 5 ⋅ 3 ⋅ 2)
= 5√6
27√6 + 7√150 = 27√6 + 5√6
= 33√6
d) ∜(1296/625)
1296 = 6 ⋅ 6 ⋅ 6 ⋅ 6 ==> 64
625 = 5 ⋅ 5 ⋅ 5 ⋅ 5 ==> 54
∜(1296/625) = ∜(64/54)
= ∜(6/5)4
= 6/5
Example 10 :
Perform the indicated operation. Assume all variables are positive.
a) 12 ∛y + 9 ∛y
b) 11 √2z − 5√2z
c) 3x7/2− 5x7/2
d) 7 ∛m7 + 3m7/3
Solution :
a) 12 ∛y + 9 ∛y
= 21∛y
b) 11 √2z − 5√2z
= 6√2z
c) 3x7/2− 5x7/2
= -2 x7/2
d) 7 ∛m7 + 3m7/3
= 7 ∛m7 + 3m7x(1/3)
= 7 ∛m7 + 3 ∛m7
= 10∛m7
Example 11 :
Perform the indicated operation. Assume all variables are positive.
a) 1254/3
b) 324/5
c) 6253/4
d) 493/2
Solution :
a) 1254/3
= (53)(4/3)
= 53 x (4/3)
= 54
= 625
b) 324/5
= (25)(4/5)
= 25 x (4/5)
= 24
= 16
c) 6253/4
= (54)(3/4)
= 54 x (3/4)
= 53
= 125
d) 493/2
= (72)(3/2)
= 72 x (3/2)
= 73
= 343
Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM