SIMPLIFYING MONOMIALS WITH NEGATIVE EXPONENTS

Negative Exponent Rule :

To change the negative exponent as positive, we have two ways.

(i) Change the place

(ii) Take the reciprocal.

Base with negative sign :

If base is having negative sign, we have to consider the power. 

  • If the power is odd, the result will also have negative sign.
  • If power is even, the result will have positive sign.

Write the expression with only positive exponents. Assume all variables represent non zero numbers. Simplify if necessary.

Problem 1 : 

4r3(r4)/ 15(r3)-2

(a) 4/15r21  (b)  4r21/15  (c)  4r9/15  (d)  4/15r9

Solution :

4r3r4315r3-24r3r1215r-6 = 4r3r12r615= 4r(3+12+6)15= 4r2115

Problem 2 : 

(-4x4y-5)3 (2x-1y)

(a) -8x5/y6  (b)  -2x3/y4  (c)  -8x-3/y4  (d)  -8x3y6

Solution :

= -4x4y-52x-1y= 2(-4)x4 x-1y y-5= -8 x4-1y1-5= -8 x3y-4-8x3y4

Problem 3 : 

[(12x-5y-3 z4) / (3xy-3z-4)]-1

(a) x4/4z8  (b)  x6/4z8  (c)  4x6/z8  (d)  x6y6/4z8

Solution :

= 12x-5 y-3 z43xy-3z-4-1= 3xy-3z-412x-5 y-3 z41= 1x1y-3z-44x-5 y-3 z4= x1+5y-3+3z-4-44= x6y0z-84= x64z8

Problem 4 : 

[(xy5) / (x3y)]-2

(a) 1/x8 y12  (b)  x4/y8  (c)  1/x5y11  (d)  y8/x4

Solution :

= [(xy5) / (x3y)]-2

[(x3y) / (xy5)]2

By distributing the power, we get

(x3x) / (y5 y]2

= (x4/y6)2

= (x8/y12)

Problem 5 :

Which is the simplified form of (3a2b3c-2)/(a-1b2c)3 ?

(a) 3a5/b3c5  (b)  3ab/c5  (c) 3/b2c5  (d) 3/ab3c5

Solution :

= 3a2b3c-2a-1b2c3= 3a2b3c-2a-3b6c3= 3 a2 a3b3 b-6 c-2 c-3= 3 a(2+3)b(3-6) c(-2-3) = 3 a5b-3 c-5 = 3a5b3c5

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