SIMPLIFY RADICAL EXPRESSIONS WITH VARIABLES

To simplify radical terms, we have to decompose the term that we have inside the radical as product of prime factors.

Then, we can take one value out of the radical sign for every two same values which are multiplied inside the radical sign.

36= 2×2×3×3= 2 × 3= 6

Add and subtract like radicals :

a+ 2a = 3 a

Multiply radical terms :

a a = aab ×cd = acdbab ×cb = acb×b acb

Divide radical terms :

ab= ab

Note :

The same rules to be followed, when we have variables.

Simplify the expressions. Assume all variables represent positive rational number.

Problem 1 :

y5/27y3

Solution :

y5 = ∛(y ∙ y ∙ y ∙ y ∙ y)

27y3 = ∛(3 ∙ 3 ∙ 3 ∙ y ∙ y ∙ y)

y5/27y3 = (y³ ∙ y²) / (3³ ∙ y³)

= y² ∙ y / 3y

= y²/3

Problem 2 :

16z3

Solution :

16z3 = ∛(2 ∙ 2 ∙ 2 ∙ 2 ∙ z ∙ z ∙ z)

= 2 2 ∙ z

= 2z 2

Problem 3 :

16a3

Solution :

16a3 = ∛(2 ∙ 2 ∙ 2 ∙ 2 ∙ a ∙ a ∙ a)

= 2 2 ∙ a

= 2a 2

Problem 4 :

b4/27b

Solution :

b4 = ∛(b ∙ b ∙ b ∙ b)

27b = ∛(3 ∙ 3 ∙ 3 ∙ b)

b4/27b = (b³ ∙ b) / (3³ ∙ b)

= b/3

Problem 5 :

x5/x²

Solution :

x5 = ∛(x ∙ x ∙ x ∙ x ∙ x)

x² = ∛(x ∙ x)

x5/x² = (x³ ∙ x²) / (x²)

=

= x

Problem 6 :

15m4n22

Solution :

= ∛15m4n22

= [(15 m m m m) (n³ n³ n³ n³ n³ n³ n³ n)]

15m4n22 = mn7 15mn

Problem 7 :

y11/y²

Solution :

y11 = ∙ y³ ∙ y³ ∙ y ∙ y

y² = y ∙ y

y11/y² = (y³ ∙ y³ ∙ y³ ∙ y ∙ y) / (y ∙ y)

= y³

Problem 8 :

20s15 t11

Solution :

= ∛20s15 t11

= [(20 s³ s³ s³ s³ s³). (t³ t³ t³ t t)]

20s15 t11 = s5 t3 20t²

Problem 9 :

32/-4

Solution :

= ∛32/∛-4

= ∛(-32/4)

= ∛-8

= -2

Problem 10 :

162x5/3x²

Solution :

= 162x5/3x²

= 54x³

= (3³ 2x³)

= 3³  2 x x x)

= 3x 2

= 3 2x

Problem 11 :

√12x4/√3x

Solution :

= √12x4/√3x

= (√12x4 × √3) / (√3x × √3)

= √36x4/√9x

= 6x²/3x

= 2x

Problem 12 :

80n5

Solution :

= 80n5

= (2³ × 10n² × n³)

= 2³ × 10n² ×

= 2n 10n²

Problem 13 :

p17q18

Solution :

= p17q18

= (p³ ∙ p³ ∙ p³ ∙ p³ ∙ p³ ∙ p²) (q³ ∙ q³ ∙ q³ ∙ q³ ∙ q³ ∙ q³)

= p5 q6

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