Problem 1 :
Given the relation R = {(-2, 3) (a, 4) (1, 9) (0, 7)} which replacement for a makes this relation a function ?
a) 1 b) -2 c) 0 d) 4
Solution :
Applying option a :
Here a = 1
R = {(-2, 3) (1, 4) (1, 9) (0, 7)}
It is not function, because 1 is having two outputs.
Applying option d :
Here a = 4
R = {(-2, 3) (4, 4) (1, 9) (0, 7)}
It is a function, because no input has more than one output.
Problem 2 :
Which relation is not a function ?
Solution :
By observing the arrow diagrams, option c the input 5 is having two different outputs 4 and 6. So, it is not a function.
Problem 3 :
If f(x) = x2 - 2x + 3, find the value of f(-2)
Solution :
f(x) = x2 - 2x + 3
f(-2) = (-2)2 - 2(-2) + 3
= 4 + 4 + 3
= 11
So, the value of f(-2) is 11.
Problem 4 :
If f(x) = (x - 2) / (x + 1), then the value of f(n + 1) is equal to
Solution :
Problem 5 :
If f(x) = 4x2 - x + 1, then f(a + 1) = ?
Solution :
f(x) = 4x2 - x + 1
f(a + 1) = 4(a+1)2 - (a+1) + 1
= 4(a2 + 2a + 1) - (a+1) + 1
= 4a2 + 8a + 4 - a - 1 + 1
= 4a2 + 7a + 4
Problem 6 :
If f(x) = x2 - 3x, find f(x/2)
Solution :
f(x) = x2 - 3x
f(x/2) = (x/2)2 - 3(x/2)
= x2/4 - 3x/2
Problem 7 :
1) Find the following values of the function.
i) f(2) = ii) f(0) =
2) For which of the values of x is this statement true ?
f(x) = 2
Solution :
1) i) f(2) = -4 ii) f(0) = 4
2) By observing the table, 2 is the output for -1.
f(-1) = 2
Problem 8 :
If the domain of f(x) = 2x + 3 is {-1, 0, 2} which number is not in range ?
a) 1 b) 2 c) 3 d) 7
Solution :
f(x) = 2x + 3
x = -1 f(-1) = 2(-1) + 3 = -2 + 3 f(-1) = 1 |
x = 0 f(0) = 2(0) + 3 = 0 + 3 f(0) = 3 |
x = 2 f(2) = 2(2) + 3 = 4 + 3 f(2) = 7 |
Range = {1, 3, 7}
In this range, 2 is not one of the element. So, option b is correct.
Problem 9 :
The function is defined by the equation y = 8x - 3. If the domain is 2 ≤ x ≤ 4, find the minimum value in the range, find the minimum value in the range of the function.
Solution :
y = 8x - 3
Domain = {2, 3, 4}
x = 2 y = 8(2) - 3 y = 16 - 3 y = 13 |
x = 3 y = 8(3) - 3 y = 24 - 3 y = 21 |
x = 4 y = 8(4) - 3 y = 32 - 3 y = 29 |
The minimum value in the range is 13.
Problem 10 :
Find the inverse of the following function
{(2, 6) (-3, 4) (-7, -5)}
Solution :
Let f(x) = {(2, 6) (-3, 4) (-7, -5)}
Relationship between the function and its inverse :
Domain of f(x) = range of inverse
range of f(x) = domain of inverse
f-1(x) = {(6, 2) (4, -3) (-5, -7)}
Problem 11 :
Find the inverse of the function
y = 3x + 2
Solution :
Problem 12 :
In which of the following graphs
Solution :
Using vertical line test, the vertical should intersect the curve maximum at one point.
So, option b is not a function..
Problem 13 :
Which graph is not a function.
Solution :
Option a is not a function.
Problem 14 :
Which graph represents one to one function
Solution :
Option a :
Using vertical line test, it is function. Using horizontal line test, it is not one to one function.
Option b :
Using vertical line test, it is function. Using horizontal line test, it is one to one function.
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM