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The rule of reflection about y = -x is
(x, y) ==> (-y, -x)

What is preimage ?
Preimage In a transformation, the original figure is called the preimage.
What is image ?
Image In a transformation, the final figure is called the image.
Reflections can be performed easily in the coordinate plane using the general rules below.
Graph the image of the figure using the transformation given.
Problem 1 :
Reflection across the line y = -x.

Solution :
By observing the coordinates of the vertices of the triangle given above.
L (1, 2), G (3, 4) and Q (4, -1)
Rule for reflection across y = -x :
(x, y) ==> (-y, -x)

Find the coordinates of the vertices of each figure after the given transformation.
Problem 2 :
Reflection across the y = -x
T(2, 2), C(2, 5), Z(5, 4), F(5, 0)
Solution :
T(2, 2), C(2, 5), Z(5, 4), F(5, 0)
Rule for reflection across y = -x :
(x, y) ==> (-y, -x)
T (2, 2) ==> T' (-2, -2)
C (2, 5) ==> C' (-5, -2)
Z (5, 4) ==> Z' (-4, -5)
F (5, 0) ==> F (0, -5)
Find the coordinates of the vertices of each figure after the given transformation.
Problem 3 :
Reflection across the line y = -x.

Solution :
By observing the figure, the coordinates are
W (-4, 2), B (-3, -1), Y (-1, 1), Z (-2, 3)
Rule for reflection across y = -x :
(x, y) ==> (-y, -x)
W (-4, 2) ==> W' (-2, 4)
B (-3, -1) ==> B' (1, 3)
Y (-1, 1) ==> Y' (-1, 1)
Z (-2, 3) ==> Z' (-3, 2)
Graph the image of the figure using the transformation given.
Problem 4 :
Reflection across the line y = -x.

Solution :
By observing the figure, the coordinates are
R (-3, 3), C (0, 0), V (-1, 5)
Rule for reflection across y = -x :
(x, y) ==> (-y, -x)
R (-3, 3) ==> R' (-3, 3)
C (0, 0) ==> C' (0, 0)
V (-1, 5) ==> V' (-5, 1)

Problem 5 :
Reflection across the line y = -x.

Solution :
By observing the figure, the coordinates are
J (-1, -3), R (-3, 2), Z (0, 2) and Y (2, -2)
Rule for reflection across y = -x :
(x, y) ==> (-y, -x)
J (-1, -3) ==> J' (3, 1)
R (-3, 2) ==> R' (2, 3)
Z (0, 2) ==> Z' (-2, 0)
Y (2, -2) ==> Y' (2, -2)

Problem 6 :
graph the polygon and its image after a reflection in the given line.
y = x

Solution :
The points shown are A(6, -3), B(1, -2) and C(4, 1)
Rule for reflection about y = x is (x, y) ==> (y, x)
A (6, -3) ==> A' (-3, 6)
B (1, -2) ==> B' (-2, 1)
C (4, 1) ==> C' (1, 4)

Problem 7 :
graph the polygon and its image after a reflection in the given line.
y = x

Solution :
The points shown are A (2, -1), B (-1, 2) C (2, 3) and D (4, 2)
Rule for reflection about y = x is (x, y) ==> (y, x)
A (2, -1) ==> A' (-1, 2)
B (-1, 2) ==> B' (2, -1)
C (2, 3) ==> C' (3, 2)
D (4, 2) ==> D' (2, 4)

Problem 8 :
graph the polygon and its image after a reflection in the given line.
y = -x

Solution :
The points shown are A (-3, 2), B (1, -1) C (-2, -2) and D (-4, -1)
Rule for reflection about y = -x is (x, y) ==> (-y, -x)
A (-3, 2) ==> A' (-2, 3)
B (1, -1) ==> B' (1, -1)
C (-2, -2) ==> C' (2, 2)
D (-4, -1) ==> D' (1, 4)

Problem 9 :
graph the polygon and its image after a reflection in the given line.
y = -x

Solution :
The points shown are A (1, 2), B (4, 2) and C (3, -2)
Rule for reflection about y = -x is (x, y) ==> (-y, -x)
A (1, 2) ==> A' (-2, -1)
B (4, 2) ==> B' (-2, -4)
C (3, -2) ==> C' (2, -3)

Problem 10 :
Graph triangle JKL with vertices J(3, 1) K (4, 2) and L(1, 3) and its image after the glide reflection.
Translation (x, y) ==> (x - 6, y - 1)
Reflection : in the line y = -x
Solution :
Given points are J(3, 1) K (4, 2) and L(1, 3)
Reflection across y = -x :
J (3, 1) ==> J' (-1, -3)
K (4, 2) ==> K' (-2, -4)
L (1, 3) ==> L' (-3, -1)
Translation of 6 units left and 1 unit down :
J' (-1, -3) ==> J'(-1 - 6, -3 - 1) ==> J'(-7, -4)
K' (-2, -4) ==> K' (-2 - 6, -4 - 1) ==> K' (-8, -5)
L' (-3, -1) ==> L' (-3 - 6, -1 - 1) ==> L' (-9, -2)

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