PROPERTIES OF ANGLES FORMED BY INTERSECTING CHORDS

If two chords intersect inside a circle, then the measure of each angle formed is one half the sum of the measures of the arcs intercepted by the angle and its vertical angle.

m1 = 1/2(mCD + mAB),

m2 = 1/2(mAD + mBC)

Find the value of x.

Problem 1 :

Solution :

x˚ = 1/2(mPS + mRQ)

x˚ = 1/2(106˚ + 174˚)

x = 1/2(280)

x = 140

Problem 2 :

Solution :

80˚ = 1/2(mAB + mCD)

80˚ = 1/2(x + 60˚)

160˚ = x + 60

x = 160 - 60

x = 100

Problem 3 :

Solution :

x˚ = 1/2(mAB + mCD)

x˚ = 1/2(190˚ + 70˚)

x = 1/2(260)

x = 130

Problem 4 :

Solution :

x˚ = 1/2(mAB + mCD)

x˚ = 1/2(66˚ + 70˚)

x = 1/2(136)

x = 68

Problem 5 :

Solution :

72˚ = 1/2(mAB + mCD)

72˚ = 1/2(x + 99˚)

144˚ = x + 99

x = 144 - 99

x = 45

Find the measure of 1.

Problem 6:

Solution :

1 = 1/2(mAD + mBC)

1 = 1/2(55˚ + 65˚)

1 = 1/2(120)

1 = 60

Problem 7 :

Solution :

1 = 1/2(mAB + mBC)

1 = 1/2(92˚ + 88˚)

1 = 1/2(180)

1 = 90

Problem 8 :

Solution :

1 = 1/2(mAD + mBC)

1 = 1/2(168˚ + 110˚)

1 = 1/2(278)

1 = 139

Find the value of x.

Problem 9 :

Solution :

x˚ = 1/2(mAD + mBC)

x˚ = 1/2(162˚ + 134˚)

x = 1/2(296)

x = 148

Problem 10:

Solution :

x˚ = 1/2(mAB + mCD)

x˚ = 1/2(25˚ + 75˚)

x = 1/2(100)

x = 50

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