PROJECTILE MOTION WORD PROBLES WORKSHEET

Problem 1 :

A rock is dropped from a 100 foot tower. The height of the rock as a function of time can be modeled by the equation: h(t) = -16t2 + 100. How long does it take for the rock to reach the ground?

Solution

Problem 2 :

A rock is dropped on the surface of Mars from a height of 100 feet. The height of a falling rock as a function of time since it was dropped on Mars can be modeled by the equation: h(t) = -6.5t2 + 100. How long does it take for the rock to hit the surface of Mars?

Solution

Problem 3 :

A ball is thrown from ground level upward at an initial velocity of 60 ft/sec. What is the ball's maximum altitude? The equation for "projectile motion" is h(t) = -16t2 + 60t. 

Solution

Problem 4 :

A ball is thrown upward from the surface of Mars with an initial velocity of 60 ft/sec. What is the ball's maximum height above the surface before it starts falling back to the surface? The equation for "projectile motion" on Mars is: h(t) = -6.5t2 + 60t

Solution

Problem 5 :

A rock is thrown upward from ground level with an initial velocity of 50 feet/sec. When will the rock hit the ground? Projectile motion can be modeled by the equation: h(t) = -16t2 + 50t.

Solution

Problem 6 :

A rock thrown upward from the surface of Mars with an initial velocity of 50 feet per second. The height of a rock can be modeled by the: h(t) = -6.5t2 + 50t. How long does it take the rock to fall back to the surface of Mars?

Solution

Problem 7 :

A rock is thrown upward from the top of a 25 foot tower with an initial upward velocity of 100 ft/sec. The height of a rock above the ground as a function of time can be modeled by the equation: h(t) = -16t2 + 100t + 25. How long does it take for the rock to:

a) reach its maximum height?

b) fall back to the ground?

Solution

Problem 8 :

A rock is thrown downward with an initial downward velocity of 50 ft/sec from the top of a 1000 foot skyscraper. The height of a falling rock as a function of time can be modeled y the equation: h(t) = -16t2 + 50t + 1000. How long does it take for the rock to hit the street below? 

Solution

Problem 9 :

A rectangle with a width of (5x + 2) feet and a length of (2x - 1) feet has an area of 100 square feet. What is the rectangle's width and length?

Solution

Problem 10 :

A rectangle with a width of (2x + 5) feet and a length of (3x - 1) feet has an area of 250 square feet. What is the rectangle's width and length?

Solution

Answer Key

1)  It takes 2.5  seconds to reach the ground.

2) So, it takes 3.

3)  maximum altitude is 56.25 feet.

4)  the maximum height is 138.46 feet.

5) So, in 3.125 sec the rock hits the ground.

6) So, it will take 7.612 sec to fall back to the surface of Mars.

7)  a) Maximum height is 181.25 feet.

b) Time to hit the ground is 6.49 sec

8)  It will take 9.61 sec to hit the street below.

9)  Width = 18.2 feet, Length = 5.48 feet

10)  Width = 20.38 feet, Length = 22.07 feet

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