Problem 1 :
The total cost function for a company is given by
C(x) = (3/4)x2 - 7x + 27
Find the level of output for which MC = AC.
a) 8 b) 6 c) 9 d) 10
Solution :
By finding the derivative of cost function, we will get the marginal cost
By dividing the cost function by output, we get average cost.
C(x) = (3/4)x2 - 7x + 27 is given
d(C(x)) = [(3/4)x2 - 7x + 27]
= (3/4) 2x - 7(1) + 0
Marginal cost = (3/2)x - 7 -----(1)
Average cost = Cost function / output
= ((3/4)x2 - 7x + 27)/x
= (3/4)x - 7 + (27/x) -----(2)
(1) = (2)
(3/2)x - 7 = (3/4)x - 7 + (27/x)
(3/2)x - (3/4)x - 7 + 7 = 27/x
(6x - 3x)/4 = 27/x
3x/4 = 27/x
3x2 = 27(4)
x2 = 27(4)/3
x2 = 9(4)
x = 6
So, the value of x is 6. Option b is correct.
Use the data, the demand function for a monopolist is given by x = 100 - 4p, where x is the number of product produced and old and p is the price per unit.
Problem 2 :
Find total revenue function
a) 25 - (x2/4) b) 25 + (x2/4) c) 25 - (x2/2)
d) 5x - (x2/4)
Solution :
To find the revenue function from the demand function, we have to multiply the number of units sold and price per unit.
x = 100 - 4p
x is number of units produced and p is the price per unit.
Let us solve for p, we get
4p = 100 - x
p = (100 - x)/4
= 25 - (x/4)
Revenue function = [25 - (x/4)] x
= 25x - (x2/4)
Problem 3 :
Find the average revenue function
a) 25 - x/6 b) 25 - x/4 c) 5 - x/4 d) 25 + x/4
Solution :
Average revenue = Total revenue / output
= [25x - (x2/4)] / x
= 25 - (x/4)
So, the answer is option b.
Problem 4 :
Find the marginal revenue function
a) 25 - (x/3) b) 25 - (x/4) c) 5 - (x/2) d) 25 - (x/2)
Solution :
By finding the derivative of total revenue, we get marginal revenue.
Total revenue = 25x - (x2/4)
d(TR) = d(25x - (x2/4))
= 25(1) - 2x/4
Marginal revenue = 25 - (x/2)
So, option d is correct.
Problem 5 :
The price and quantity at which MR = 0
a) 50, 12.5 b) 70, 12.5 c) 100, 12.5 d) 70, 10
Solution :
Marginal revenue = 25 - (x/2)
25 - (x/2) = 0
25 = x/2
x = 25(2)
x = 50
Number of quantity produced = 50
To find price per unit, we have to apply in the function x = 100 - 4p
50 = 100 - 4p
4p = 100 - 50
4p = 50
p = 50/4
p = 12.5
So, option a is correct.
Use the data, A firm knows that the demand function for one of its products is linear. It also knows that it can sell 1000 units when the price is $4 per unit and it can sell 1500 units when the price is 2 per unit.
Problem 6 :
Find the demand function.
a) 2000 - 250p b) 2000 - 5p c) 2000 + 5p
d) 2000 - 25p
Solution :
Since the given function is linear, the function will be in the form
y = mx + b ----(1)
(4, 1000) and (2, 1500)
m = (y2 - y1)/(x2 - x1)
= (1500 - 1000)/(2 - 4)
= 500/(-2)
= -250
Applying slope (m) = -250 in (1), we get
y = -250x + b
Applying any point here, we get
1000 = -250(4) + b
1000 = -1000 + b
b = 2000
y = -250x + 2000
y = 2000 - 250x
x = p
y = 2000 - 250p
So, option a is correct.
Problem 7 :
Find the total revenue function
a) (8 - x2)/250 b) (8x - x2) / 50 c) (8x - x2)/250
a) (8x - x2)/25
Solution :
Total function is the product of number of units sold by price per unit.
Revenue = demand x price pre unit
Demand function = y = 2000 - 250x
Dividing by 250, we get
y = (8 - x) / 250
Price per unit = x
y = (8 - x)x / 250
= (8x - x2) / 250
so, option c is correct.
Problem 8 :
Find the average revenue function
a) (8 - x) / 50 b) (8 - x) / 25 c) (8 + x) / 250
d) (8 - x)/ 250
Solution :
Average revenue = Total revenue / output
= [(8x - x2) / 250] / x
= (8 - x) / 250
So, option d is correct.
Problem 9 :
Find the marginal revenue function
a) 8 - x/12 b) 8 - x/25 c) 8 - x/125
d) 8 + x/125
Solution :
By finding derivative of total revenue, we get marginal revenue.
Total revenue = (8x - x2) / 250
d(Total revenue) = d[(8x - x2) / 250]
= 8(1) - 2x/250
= 8 - x/125
So, option c is correct.
May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM