PROBLEMS ON REGULAR POLYGON

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A polygon is a closed plane figure which has straight lines for sides.

Regular polygon has all sides equal in length and all angles equal in size.

The sum of interior angles of n sided polygon is 

s = (n - 2) x 180°

Measure of each angle= (n-2)×180n

Number of sides

3

4

5

6

7

8

9

10

Name of the polygon

Triangle

Quadrilateral

Pentagon

Hexagon

Heptagon

Octagon

Nonagon

Decagon

Problem 1 :

Find the number of sides of a regular polygon which has angles of 150°

Solution :

Sum of the angles of a regular polygon = 150

Let n be the number of sides.

Measure of each angle= (n-2)×180n= (n-2)×180n

n = 12

So, the number of sides of a required polygon is 12.

Problem 2 :

Is there a regular polygon which has the angle of 158°

Solution :

Measure of each angle= (n-2)×180n158= (n-2)×180n158 n = (n -2)×180158n180 = n - 279n90 = n - 22 = n - 79n902 = 90n - 79n902 = 11n9018011 = n

Here we get the value of n as decimal. So, there is no such regular polygon is having an angle of 158°.

Problem 3 :

For the following regular polygon given below,

a) Equilateral triangle

b) Square

c) Pentagon

d)  Hexagon

e) Octagon

f) Decagon

find

(i)  Number of sides that the polygon has

(ii) Number of angles

(iii)  Size of each angle.

Solution :

a) Equilateral triangle

Number of sides = 3, number of angles = 3

Measure of each angle= (3-2)×1803Each angle measure of equilateral triangle= 1803= 60°

b) Square

Number of sides = 4, number of angles = 4

Measure of each angle= (4-2)×1804Each angle measure of square = 3604= 90°

c) Pentagon

Number of sides = 5, number of angles = 5

Measure of each angle= (5-2)×1805Each angle measure of pentagon = 5405= 108°

d) Hexagon

Number of sides = 6, number of angles = 6

Measure of each angle= (6-2)×1806Each angle measure of hexagon = 7206= 120°

e) Octagon

Number of sides = 8, number of angles = 8

Measure of each angle= (8-2)×1808Each angle measure of octagon = 7208= 135°

f) Decagon

Number of sides = 10, number of angles = 10

Measure of each angle= (10-2)×18010Each angle measure of decagon = 144010= 144°

Problem 4 :

In an equilateral hexagon, four of the exterior angles each have a measure of x°. The other two exterior angles each have a measure of twice the sum of x and 48. Find the measure of each exterior angle.

Solution :

Number of sides of hexagon = 6

Four exterior angle of each = x

The other two exterior angle = 2(x + 48)

Sum of exterior angle of polygon = 360

4x + 2[2(x + 48)] = 360

4x + 2(2x + 96) = 360

4x + 4x + 192 = 360

8x = 360 - 192

8x = 168

x = 21

So, the four angle measures are 21, 21, 21 and 21.

The other angle measure = 2(21 + 48)

= 2(69)

= 138

So, the required angle are 21, 21, 21, 21, 138 and 138.

Problem 5 :

Is the hexagon a regular hexagon. Explain your reasoning.

problems-on-regular-polygon-q1

Solution :

If it is regular polygon, then the interior angle should be the same. Since the interior angle measures are not the same, it cannot be a regular hexagon.

Problem 6 :

Describe and correct the error in finding the measure of one exterior angle of a regular pentagon.

problems-on-regular-polygon-q2.png

Solution :

One interior angle of polygon = (n - 2) (180/n)

Interior angle + exterior angle = 180

Interior angle = 540/number of sides

= 540/5

= 108

108 + exterior angle = 180

exterior angle = 180 - 108

= 72

72 degree is the exterior angle.

Problem 7 :

Find the number of sides for the regular polygon described.

Each interior angle has a measure of 156°.

Solution :

One interior angle of polygon = (n - 2) (180/n)

156 = (n - 2) (180/n)

156n = 180n - 360

180n - 156n = 360

24n = 360

n = 360/24

n = 15

So, the number of sides of a regular polygon is 15.

Problem 8 :

A home plate for a baseball field is shown.

a. Is the polygon regular? Explain your reasoning.

b. Find the measures of ∠C and ∠E.

problems-on-regular-polygon-q3.png

Solution :

a) The polygon is not equilateral or equiangular. So, the polygon is not regular.

b. Find the sum of the measures of the interior angles.

(n − 2) ⋅ 180° = (5 − 2) ⋅ 180° ==> 540°

x° + x° + 90° + 90° + 90° = 540°

2x + 270 = 540

x = 135

So, m∠C = m∠E = 135°.

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