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The rule of reflection about y = x is
(x, y) ==> (y, x)

What is preimage ?
Preimage In a transformation, the original figure is called the preimage.
What is image ?
Image In a transformation, the final figure is called the image.
Reflections can be performed easily in the coordinate plane using the general rules below.
Graph the image of the figure using the transformation given
Problem 1 :
Reflection over y = x

Solution :
By observing the coordinates of the vertices of the triangle given above
X (0, 5), L (-3, 1) and U (-3, 5)
Rule for reflection across y = x :
(x, y) ==> (y, x)
X (0, 5) ==> X’ (5, 0)
L (-3, 1) ==> L’ (1, -3)
U (-3, 5) ==> U’ (5, -3)

Problem 2 :
Reflection over y = x

Solution :
By observing the coordinates of the vertices of the triangle given above
L (1, 2), G (3, 4) and Q (4, -1)
Rule for reflection across y = x:
(x, y) ==> (y, x)
L (1, 2) ==> L’ (2, 1)
G (3, 4) ==> G’ (4, 3)
Q (4, -1) ==> Q’ (-1, 4)

Problem 3 :
Reflection across the line y = x
T (2, 2), C (2, 5), Z (5, 4), F (5, 0)
Solution :
Rule for reflection across y = x:
(x, y) ==> (y, x)
T (2, 2) ==> T’ (2, 2)
C (2, 5) ==> C’ (5, 2)
Z (5, 4) ==> Z’ (4, 5)
F (5, 0) ==> F’ (0, 5)

Problem 4 :
Reflection across the line y = x
H (-1, -5), M (-1, -4), B (1, -2), C (3, -3)
Solution :
Rule for reflection across y = x :
(x, y) ==> (y, x)
H (-1, -5) ==> H’ (-5, -1)
M (-1, -4) ==> M’ (-4, -1)
B (1, -2) ==> B’ (-2, 1)
C (3, -3) ==> C’ (-3, 3)

Problem 5 :
Plot the points A (–2, 0), B (4, 0), C (1, 4) and D (–2, 4) on a graph paper.
Point D is reflected about the line x = 1 to get the image E.
Write the coordinates of E. Name the figure ABED.
Solution :
By plotting the given coordinates, we get

The horizontal distance between each point and the line of reflection,
A(-2, 0) :
The horizontal distance between A and x = 1 is 3 units towards the left, then we have to move the 3 units towards the right.
A'(4, 0)
B (4, 0) :
The horizontal distance between B and x = 1 is 3 units towards the right, then we have to move the 3 units towards the left.
B' (-2, 0)
C (1, 4) :
Since the point is on the line of reflection, so there is no change in the point C.
C' (1, 4)
D (2, 4) :
The horizontal distance between D and x = 1 is 1 unit towards the right, then we have to move the 1 unit towards the left.
D' (0, 4)

Problem 6 :
Use graph paper for this question:
(a) The point P(2, 3) is reflected in the line x = 4 to the point P′. Write the coordinates of P′.
(b) Find the image of the point Q(1, –2) in the line x = –1.
Solution :
a)

The horizontal distance between P(2, 3) and the line of reflection x = 4 is 2 units to the left, to find the point of reflection, we have to move 2 units to the right from the line of reflection.
P(2, 3) ==> P'(6, 3)
(b) The horizontal distance between the point Q(1, –2) and the line of reflection x = –1 is 2 units to the right, so we have to move 2 units left from the line of reflection.
x = -1 - 2
Q'(-3, -2)

Problem 7 :
Use graph paper for this question :
Find the coordinates of the image of (3, 1) under reflection in x-axis followed by reflection in the line x = 1.
Solution :
Given point is (3, 1),
the horizontal distance between the point and line of reflection x = 1 is 2 units towards right, so we have to move the same 2 units left from the line of reflection.
(3, 1) ==> (1 - 2, 1) ==> (-1, 1)

Problem 8 :
Use graph paper for this question:
Points A and B have coordinates (2, 5) and (0, 3) respectively.
Find
(a) the image A' of A under reflection in x-axis.
(b) the image B' of B under reflection in the line AA'.
Solution :
A (2, 5) and B (0, 3)
a) Reflection across x-axis :
(x, y) ==> (x, -y)
A (2, 5) ==> A' (2, -5)

B (0, 3)
The horizontal distance from (0, 3) to the vertical line is 2 units. From the line of reflection, we have to move 2 units to the right.
2 + 2 ==> 4
B' (4, 3)
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May 21, 24 08:51 PM
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