PRACTICE QUESTIONS ON MEAN MEDIAN MODE

Mean :

The arithmetic mean of a given data is the sum of all observations divided by the number of observations.

Mean  =  (Sum of all observations)/Number of observations

Median :

The median is the middle value of a given data when those values are arranged from ascending to descending order.

Median  =  Middle value

To find the median from ungrouped data, we have to consider if n is odd or even.

If n is odd, then using the formula

Median   =  (n+1)th term/2

If n is even, then using the formula

Median  =  [(nth/2) term + (n/2+1)th term]/2

Mode :

The mode is the value that occurs most often in the given data.

Find the mean of the numbers.

Problem 1 :

2, 4, 1, 0, 1, and 1

Solution :

Given, 2, 4, 1, 0, 1, and 1

Mean = (sum of the terms)/(number of the terms)

= (2 + 4 + 1 + 0 + 1 + 1)/6

= 9/6

= 3/2

= 1.5

Hence the mean is 1.5

Problem 2 :

$270, $310.50, $243.75, and $252,15

Solution :

Given, $270, $310.50, $243.75, and $252,15

Mean = (sum of the terms)/(number of the terms)

= ($270 + $310.50 + $243.75 + $252.15)/4

= $1076.4/4

= $269.1

Hence the mean is 269.1

Problem 3 :

Each workday last week, Yoshie kept track of the number of minutes she had to wait for the bus. She waited 3, 0, 8,1 and 8 minutes. Find the mean.

Solution :

The number of minutes = 3, 0, 8, 1 and 8

Mean = (sum of the terms)/(number of the terms)

= (3 + 0 + 8 + 1 + 8)/5

= 20/5

= 4

Hence the mean is 4.

Problem 4 :

In the last three months, Raul’s water bills were $31.45, $48.76, and $42. 60. Find the mean.

Solution :

Raul’s water bills = $31.45, $48.76, and $42. 60.

Mean = (sum of the terms)/(number of the terms)

= ($31.45 + $48.76 + $42.60)/3

= $122.81/3

= $40.94

Hence the mean is $40.94.

Find the Median of a Set of Numbers.

Problem 5 :

41, 45, 32, 60, 58

Solution :

Given, 41, 45, 32, 60, 58

Arrange the data in ascending order.

= 32, 41, 45, 58, 60

n = 5

Median = ((n + 1)/2)th term

= ((5 + 1)/2)th term

= (6/2)th term

= 3 term

= 45

Hence the median is 45.

Problem 6 :

25, 23, 24, 26, 29, 19, 18, 32

Solution :

Given, 25, 23, 24, 26, 29, 19, 18, 32

Arrange the data in ascending order.

= 18, 19, 23, 24, 25, 26, 29, 32

n = 8(even)

Median = ((n/2)th term + (n/2 + 1)th term)/2

= ((8/2)th term + (8/2 + 1)th term)/2

= (4th term + 5th term)/2

= (24 + 25)/2

= 49/2

Hence the median is 24.5

Problem 7 :

The ages of the eight men in Jerry’s model train club are 52, 63, 45, 51, 55, 75, 60, and 59. Find the median age.

Solution :

Number of ages = 52, 63, 45, 51, 55, 75, 60, and 59. 

Arrange the data in ascending order.

= 45, 51, 52, 55, 59, 60, 63, 75

n = 8(even)

Median = ((n/2)th term + (n/2 + 1)th term)/2

= ((8/2)th term + (8/2 + 1)th term)/2

= (4th term + 5th term)/2

= (55 + 59)/2

= 114/2

= 56

Hence the median age is 56.

Problem 8 :

The number of clients at Miranda’s beauty salon each weekday last week were 18, 7, 12, 16, and 20. Find the median number of clients.

Solution :

Number of clients = 18, 7, 12, 16, and 20.

Arrange the data in ascending order.

= 7, 12, 16, 18, 20

n = 5(odd)

Median = ((n + 1)/2)th term

= ((5 + 1)/2)th term

= (6/2)th term

= 3 term

= 16

Hence the median is 16.

Find the Mode of a Set of Numbers.

Problem 9 :

6, 4, 4, 5, 6, 6, 4, 4. 4, 3, 5

Solution :

Given, 6, 4, 4, 5, 6, 6, 4, 4. 4, 3, 5

Mode is the most repetitive value of a given set of values.

= 4, 5, 6

So, the mode is 4, 5, 6.

Problem 10 :

The number of siblings of a group of students :

2, 0, 3, 2, 4, 1, 6, 5, 4. 1, 2, 3

Solution :

Given, 2, 0, 3, 2, 4, 1, 6, 5, 4. 1, 2, 3

Mode is the most repetitive value of a given set of values.

= 1, 2, 3, 4

So, the mode is 1, 2, 3, 4.

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