PARALLEL PERPENDICULAR AND INTERSECTING LINES

Problem 1 :

Line A passes through the points (4, 6) and (-3, 2). What is the slope of a line that is parallel to line A?

Solution:

Line A passes through the points (4, 6) and (-3, 2).

slope m=y2-y1x2-x1Substitute (x1,y1)=(4, 6) and (x2,y2)=(-3, 2)m=2-6-3-4m=-4-7m=47

Problem 2 :

Line B passes through the points (-1, 0) and (4, -7). What is the slope of a line that is parallel to line B?

Solution:

Line B passes through the points (-1, 0) and (4, -7).

slope m=y2-y1x2-x1Substitute (x1,y1)=(-1,0) and (x2,y2)=(4,-7)m=-7-04+1m=-75

Problem 3 :

Line C passes through the points (5, -10) and (15, 20). What is the slope of a line that is perpendicular to line C?

Solution:

Line C passes through the points (5, -10) and (15, 20).                                                

slope m=y2-y1x2-x1Substitute (x1,y1)=(5,-10) and (x2,y2)=(15,20)m=20-(-10)15-5m=3010m=3Perpendicular slope=-1m=-13

Problem 4 :

Line D passes through the points (12, 3) and (15, 6). What is the slope of a line that is perpendicular to line D?

Solution:

Line D passes through the points (12, 3) and (15, 6).     

slope m=y2-y1x2-x1Substitute (x1,y1)=(12,3) and (x2,y2)=(15,6)m=6-315-12m=33m=1Perpendicular slope=-1m=-11=-1

Problem 5 :

Find an equation of a line that is parallel to y = 2x + 4 with a y-intercept at (0, -7).

Solution:

When  two line are parallel, their slopes are equal.

y = 2x + 4 

Slope m = 2

y = mx + b

Substitute (x, y) = (0, -7)

-7 = 2(0) + b

b = -7

So, the equation of the line as y = 2x - 7.

Problem 6 :

Find an equation of a line that is parallel to y-3=-12(x-9) with a y-intercept at (0,3).

Solution:

y-3=-12(x-9)Slope m = -12y=mx+bSubstitute (x,y)=(0,3)3=-12(0)+bb=3

So, the equation of the line as

y=-12x+3

Problem 7 :

Find an equation of a line that is parallel to y = 3x - 14 that passes through the point (4, 5). 

Solution:

y = 3x - 14

Slope m = 3

y - y1 = m(x - x1)

Substitute (x1, y1) = (4, 5).

y - 5 = 3(x - 4)

y - 5 = 3x - 12

y = 3x - 12 + 5

y = 3x - 7

Problem 8 :

Find an equation of a line that is perpendicular to y=-23x+9 with a y-intercept at (0, -4).

Solution:

y=-23x+9Slope m = 32y=mx+bSubstitute (x, y)=(0,-4)-4=32(0) + bb=-4

So, the equation of the line as

y=32x-4

Problem 9 :

Find an equation for the line that is perpendicular to y + 2 = 2(x - 5) with a y-intercept at (0, -7).

Solution:

y + 2 = 2x - 10

y = 2x - 12

Slope m = 2

Perpendicualr slope=-1m=-12Substitute (x,y)=(0,-7)y=mx+b-7=-12(0)+bb=-7

So, the equation of the line as

y=-12x-7

Problem 10 :

Find an equation of a line that is perpendicualr to y=45x+3 that passes through the point (1,2).

Solution:

y=45x+3y=mx +bm=45Perpendicualr slope=-1m=-145m=-54Substitute (x, y)=(1,2)2=-54(1)+b2=-54+bb=134

So, the equation of the line as

y=-5x4+134

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