ORDER OF OPERATIONS USING PEMDAS

To evaluate expressions that involve more than one operation, we will use a set of rules called the order of operations.

PEMDAS is the rule that can be used to simplify or evaluate complicated numerical expressions with more than one  operation.

Note :

In some expressions, if there is multiplication and division, we have to do the operations one by one in the order from left to right.

Problem 1 :

2 + 11 × 3

Solution :

2 + 11 × 3

= 2 + 33

= 35

Multiplication

Addition

Problem 2 :

15 ÷ 5 - 2

Solution :

15 ÷ 5 - 2

= 3 - 2

= 1

Division

Subtraction

Problem 3 :

54 ÷ 3 - 2 × 4

Solution :

54 ÷ 3 - 2 × 4

= 18 - × 4

= 18 - 8

= 10

Division 1st (L to R)

Multiplication

Subtraction

Problem 4 :

14 × 3 + 28 ÷ 7

Solution :

14 × 3 + 28 ÷ 7

= 42 + 28 ÷ 7

= 42 + 4

= 46

Multiplication

Division

Addition

Problem 5 :

100 ÷ 5 × 3 - 46

Solution :

100 ÷ 5 × 3 - 46

= 20 × 3 - 46

= 60 - 46

= 14

Division 1st (L to R)

Multiplication

Subtraction

Problem 6 :

40 × 6 ÷ (9 + 21)

Solution :

40 × 6 ÷ (9 + 21)

40 × 6 ÷ 30

= 240 ÷ 30

= 8

Parenthesis ( )

Multiplication

Division

Problem 7 :

72 + 3

Solution :

= 7+ 3

= 49 + 3

= 52

Exponent

Addition

Problem 8 :

5× 32

Solution :

= 5× 32

= 25 × 9

= 225

Exponents

Multiplication

Problem 9 :

8÷ (9 - 5)

Solution :

= 8÷ (9 - 5)

8÷ 4

= 64 ÷ 4

= 16

Parenthesis ( )

Exponent

Division

Problem 10 :

(17 - 6 ÷ 2) × (12 + 11)

Solution :

(17 - 6 ÷ 2) × (12 + 11)

= (17 - 3) × 23

= 14 × 23

= 322

Parenthesis ( )

Parenthesis ( )

Multiplication

Problem 11 :

A school lunch contains 12 chicken nuggets. Ninety-five students buy the lunch. What is the total number of chicken nuggets served?

Solution :

Number of chicken nuggets in a school lunch = 12

Number of students buying the lunch = 95

Total number of nuggets = 12 x 95

= 1140

So, total number of chicken nuggets served.

Problem 12 :

You make 24 equal payments for a go-kart. You pay a total of $840. How much is each payment?

Solution :

Worth of total payment = $840

Number of equal payments = 24

Cost of each payment = 840/24

= 35

So, worth of each paymet is $35.

Determine the operation you would use to solve the problem. Do not answer the question.

Problem 13 :

Gymnastic lessons cost $30 per week. How much will 18 weeks of gymnastic lessons cost?

Solution :

Cost of lessons = $30

Number of weeks = 18

Cost of 18 weeks lessons = 18 x 30

= $540

So, cost of 18 weeks lesson is $540.

Problem 14 :

The scores on your first two tests were 82 and 93. By how many points did your score improve?

Solution :

First test score = 82

Second test score = 93

Number of points improved = 93 - 82

= 11

So, 11 points are improved.

Problem 15 :

You are setting up tables for a banquet for 150 guests. Each table seats 12 people. What is the minimum number of tables you will need?

Solution :

Number of guests = 150

Number of seats in each table = 12

Number of tables = 150/12

=  12.5

So, the minimum number of tables you need is 12.

Problem 16 :

A store has 15 boxes of peaches. Each box contains 45 peaches. How many peaches does the store have?

Solution :

Number of boxes = 15

Number of peaches each box contains = 45

Number of peaches the store has = 45 x 15

= 675 peaches

Problem 17 :

Two shirts cost $18 and $25. What is the total cost of the shirts? 

Solution :

Cost of two shits = 18 and 25

Total cost of two shirts = 18 + 25

= 43

So, the required cost is $43.

Problem 18 :

A gardener works for 14 hours during a week and charges $168. How much does the gardener charge for each hour?

Solution :

Number of hour works during a week = 14

Total charge = $168

Amount for each hour = 168/14

= 12

So, charge per hour is $12.

Problem 19 :

Which number is equivalent to the expression below? 

⋅ 42 + 3(6 ÷ 2)

a)  25     b)  73      c)  41     d)  105

Solution :

= 2 ⋅ 42 + 3(6 ÷ 2)

⋅ 16 + 3(6 ÷ 2)

⋅ 16 + 3(3)

= 32 + 9

= 41

So, option c is correct.

Problem 20 :

A field hockey field is rectangular. Its width is 54.88 meters, and its length is 91.46 meters. Find the perimeter of the field.

Solution :

Width = 54.88 meter

Length = 91.46 meter

Perimeter = 2(length + width)

= 2(54.88 + 91.46)

= 2 (146.34)

= 292.68

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