OPERATIONS WITH COMPLEX NUMBERS

Complex number will consists of two parts,

(i) Real part

(ii) Imaginary part

General form of complex number is a + ib

Here a is real and b is imaginary.

How to add complex numbers ?

Consider two complex numbers,

Let z1 = a + ib and z2 = c + id

z+ z2 = a + ib + c + id

= (a + c) + ib + id

= (a + c) + i(b + d)

Combining the real parts and combining imaginary parts.

How to subtract complex numbers ?

Consider two complex numbers,

Let z1 = a + ib and z2 = c + id

z+ z2 = a + ib - (c + id)

= (a + c) - ib - id

= (a + c) - i(b + d)

Combining the real parts and combining imaginary parts.

How to multiply complex numbers ?

Consider two complex numbers,

Let z1 = a + ib and z2 = c + id

zz2 = (a + ib)(c + id)

= ac + iad + ibc + i2bd

= ac + iad + ibc + (-1)bd

= ac - bd + i(ad + bc)

Conjugate of complex numbers ?

Let z = 2 + 3i

To find conjugate of any complex number, we have to change sign of imaginary number.

z̄ = 2 - 3i

Dividing complex numbers :

To divide a complex number by another complex number, we have to multiply by the conjugate of the denominator.

Evaluate the expression and write your answer in the form a + bi.

Problem 1 :

(5 - 6i) + (3 + 2i)

Solution:

= (5 - 6i) + (3 + 2i)

= 5 - 6i + 3 + 2i

= 8 - 4i

Problem 2 :

4-12i-9+52i

Solution:

=4-12i-9+52i=4-12i-9-52i=-5-3i

Problem 3 :

(2 + 5i)(4 - i)

Solution:

= (2 + 5i)(4 - i)

= 8 - 2i + 20i - 5i2

= 8 + 18i + 5

= 13 + 18i

Problem 4 :

(1 - 2i)(8 - 3i)

Solution:

= (1 - 2i)(8 - 3i)

= 8 - 3i - 16i + 6i2

= 8 - 19i - 6

= 2 - 19i

Problem 5 :

12+7i

Solution:

=12+7i=12-7i

Problem 6 :

2i12-i

Solution:

=2i12-i=2i12+i

Problem 7 :

1+4i3+2i

Solution:

=1+4i3+2i=1+4i3+2i×3-2i3-2i=3-2i+12i-8i29-6i+6i-4i2=3+10i+89+4=11+10i13=1113+1013i

Problem 8 :

3+2i1-4i

Solution:

=3+2i1-4i=3+2i1-4i×1+4i1+4i=3+12i+2i+8i21+4i-4i-16i2=3+14i-81+16=-5+14i17=-517+1417i

Problem 9 :

11+i

Solution:

=11+i=11+i×1-i1-i=1-i1-i+i-i2=1-i1+1=1-i2=12-12i

Problem 10 :

34-3i

Solution:

=34-3i=34-3i×4+3i4+3i=12+9i16-9i2=12+9i16+9=12+9i25=1225+925i

Problem 11 :

i3

Solution:

= i3

= i2 × i

= -1 × i

= -i

Problem 12 :

i100

Solution:

= i100

= (i2)50

= (-1)50

= ((-1)2)25

= 125

= 1

Problem 13 :

√-25

Solution:

=-25=25(-1)=25-1=5i

Problem 14 :

√-3√-12

Solution:

=-3×-12=(3)(-1)×(12)(-1)=3-1×12-1=3i×23i=2×3i2=-6

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