NEGATIVE INDEX LAW

Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.

If a is any non zero number and n is an integer, then

a-n = 1/an

This means an and a-n are reciprocal to each other.

Simplify the following and give answer in simplest rational form :

Problem 1 :

4-1

Solution :

4-1 = 1/4

Problem 2 :

9-2

Solution :

9-2 = 1/92

Here, 92 = 9 x 9

= 1/(9 x 9)

= 1/81

Problem 3 :

3-3

Solution :

3-3 = 1/33

Here, 3= 3 x 3 x 3

= 1/(3 x 3 x 3)

= 1/27

Problem 4 :

10-5

Solution :

10-5 = 1/105

Here, 10= 10 x 10 x 10 x 10 x 10

= 100000

So, the answer is

= 1/100000

Problem 5 :

(1/2)-1

Solution :

(1/2)-1

Here the base is fraction, when we take the reciprocal of base, we get 2/1

(1/2)-1 = (2/1)1

Now distributing the power for numerator and denominator, we get

= 2/1

So, the answer is 2.

Problem 6 :

(2/3)-2

Solution :

(2/3)-2

Here the base is fraction, when we take the reciprocal of base, we get 3/2

(2/3)-2 (3/2)2

Distributing the power for both numerator and denominator, we get

= 9/4

Problem 7 :

(1  3/4)-2

Solution :

(1  3/4)-2

Converting the mixed fraction into improper fraction, we get

1  3/4 = 7/4 

(1  3/4)-2 = (7/4)-2

= (4/7)2

Distributing the power, we get

= 16/49

Problem 8 :

20 + 2-1

Solution :

20 + 2-1

= 1 + (1/2)

= 3/2

Problem 8 :

20 + 2-1

Solution :

20 + 2-1

= 1 + (1/2)

= 3/2

Problem 9 :

30 + 31 - 3-1

Solution :

= 30 + 3- 3-1

= 1 + 3 - (1/3)

= 4 - (1/3)

= 11/3

Problem 10 :

2a-1

Solution :

= 2a-1

= 2(1/a)

= 2/a

Problem 11 :

(5c)-2

Solution :

= (5c)-2

Converting the negative exponent as positive exponent.

= 1/(5c)2

= 1/25c2

Problem 12 :

2(ab)-1

Solution :

= 2(ab)-1

Converting the negative exponent as positive exponent.

= 2(1/(ab))

= 2/ab

Problem 13 :

2ab-1

Solution :

= 2ab-1

Converting the negative exponent as positive exponent.

= 2a(1/b)

= 2a/b

Problem 14 :

(3n-2)-1

Solution :

= (3n-2)-1

Considering the innermost term,

= [3(1/n2)]-1

= [3/n2]-1

= n2 / 3

Write each of the followings as fractions

Problem 14 :

8-2/3

Solution :

= 8-2/3

Writing 8 in exponential form, we get

8 = 2 • 2 • 2

= 23

8-2/3 = (23)-2/3

23(-2/3)

2-2

= 1/22

= 1/4

Problem 15 :

25-3/2

Solution :

= 25-3/2

Writing 25 in exponential form, we get

25 = 5 • 5

= 52

25-3/2 = (52)-3/2

= 5• (-2/3)

= 5-2

= 1/52

= 1/25

Problem 16 :

Arrange in order from smallest to largest

1/50, 5-2, 3/10, 2-3

Solution : 

1/50 = 0.05

5-2 = 1/52

= 1/25

= 0.04

3/10 = 0.3

2-3 1/23

= 1/8

= 0.125

Arranging from smallest to greatest, 

0.04, 0.05, 0.3, 0.125

Arranging in exponential form, we get

5-2, 1/50, 3/10, 2-3

Problem 17 :

Simplify : 2-2 + 3-2 x 2-3

Solution : 

= 2-2 + 3-2 x 2-3

Converting each negative exponent to positive exponent, we get

= 1/2 + 1/32 x 1/23

= 1/4 + 1/9 x 1/8

Using order of operation, we have to perform multiplication first.

= 1/4 + 1/72

Least common multiple of 4 and 72 is 72

= (1/4) x (18/18) + 1/72

= 18/72 + 1/72

= (18 + 1)/72

= 19/72

Problem 18 :

Given that 

2+ 2= 9/32

Work out mn

Solution : 

2+ 2= 9/32

2+ 2= (1 + 8)/32

Decomposing into two fractions, we get

2+ 2= 1/32 + 8/32

= 1/32 + 1/4

= 1/25 + 1/22

2+ 2n  = 2-52-2

Comparing the exponents, we get

m = -5 and n = -2

mn = -5(-2)

= 10

Problem 19 :

Put the expressions above in order, from smallest to largest,

when: x = 2 and x = 0.5

x-2, x0, x, x3

Solution :

Given that, x-2, x0, x, x3

Changing the negative exponents into positive exponents, we get

= 1/x2x0, x, x3

By applying x = 2, we get

= 1/22, 20, 2, 23

= 1/4, 1, 2, 8

It is in the order from least to greatest.

By applying x = 0.5, we get

= 1/0.52, 0.50, 0.5, 0.53

= 1/0.25, 1, 0.5, 0.125

= 4, 1, 0.5, 0.125

Arranging from least to greatest, we get

= 0.125, 0.5, 1, 4

Problem 20 :

What is the value of the missing exponent in the equation (3x?y4)-3 = x6/27y12 ?

a) 2    b)  -2   c)  3   d) -3

Solution :

(3x?y4)-3 = x6/27y12

Converting the negative exponent to positive, we get

1/(3x?y4)3 = x6/27y12

1/(33(x?)3(y4)3) = x6/27y12

1/(27(x?)3(y12) = x6/27y12

Let a be the unknown

x-3a = x6

-3a = 6

a = -6/3

a = -2

So, the missing digit is -2.

Problem 21 :

Which expression is equivalent to (-3 • 6• 4)-2 ?

a) -144    b)  144   c)  1/144   d) -1/144

Solution :

= (-3 • 6• 4)-2

Anything to the power 0 is 1.

= (-3 • 4)-2

= 1/(-12)2

= 1/144

So, option c is correct.

Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.

Recent Articles

  1. Finding Range of Values Inequality Problems

    May 21, 24 08:51 PM

    Finding Range of Values Inequality Problems

    Read More

  2. Solving Two Step Inequality Word Problems

    May 21, 24 08:51 AM

    Solving Two Step Inequality Word Problems

    Read More

  3. Exponential Function Context and Data Modeling

    May 20, 24 10:45 PM

    Exponential Function Context and Data Modeling

    Read More