LAWS OF EXPONENTS WORKSHEET

Simplify using laws of exponents :

1)  54 x 57

2)  d2 x d6

3)  k8 ÷ k3

4)  75 ÷ 76

5)  (x2)5

6)  (34)4

7)  p3 ÷ p7

8)  n9 x n3

9)  (5t)3

10)  7x · 72

11)  103 ÷ 10q

12)  (c4)m

13)  (6x2) (4x2)

14)  (3x3y2)(-6 y5)

15)  (5p3)(-m8 p2)

16)  (10gh8 v6) (11g h8)

17)  (4 fh3) (-5 f6) (-3 h2

18)  (-22 x3 y4) ((-3)2 x4 y4)

19)  (3 xa yb zc )(-yf zg )

20)  (x2 y)4

Detailed Solution

Problem 1 :

54 x 57

Solution :

= 54 x 57

Since the bases are same, we have to use only one base and add the powers.

= 54+7

= 511

Problem 2 :

d2 x d6

Solution :

d2 x d6

Since the bases are same, we have to use only one base and add the powers.

= d2 + 6

= d8

Problem 3 :

k8 ÷ k3

Solution :

k8 ÷ k3

Since the bases are same, we have to use only one base and subtract the powers.

= k8 - 3

= k5

Problem 4 :

75 ÷ 76

Solution :

75 ÷ 76

Since the bases are same, we have to use only one base and subtract the powers.

= 75 - 6

= 7-1

By changing the negative exponent as positive, we have to change flip the base.

= (1/7)1

= 1/7

So, the answer is 1/7.

Problem 5 :

(x2)5

Solution :

(x2)5

Since we have power raised by another power, we have to multiply the powers.

x2·5

= x10

So, the answer is x10.

Problem 6 :

(34)4

Solution :

(34)4

Since we have power raised by another power, we have to multiply the powers.

= 34·4

= 316

So, the answer is 316.

Problem 7 :

p3 ÷ p7

Solution :

p3 ÷ p7

Since the bases are same, we have to use only one base and subtract the powers.

= p3 - 7

= p-4

By changing the negative exponent as positive, we have to change flip the base.

= (1/p)4

= 1/p4

So, the answer is 1/p4.

Problem 8 :

n9 x n3

Solution :

n9 x n3

Since the bases are same, we have to use only one base and add the powers.

= n3 + 9

= n12

Problem 9 :

(5t)3

Solution :

(5t)3

Since we have power raised by another power, we have to multiply the powers.

= 5t(3)

= 53t

Problem 10 :

7x · 72

Solution :

7x · 72

Since bases are multiplied, we have to put the base once and add the powers. 

= 7(x + 2)

So, the answer is 7(x + 2).

Problem 11 :

103 ÷ 10q

Solution :

103 ÷ 10q

Since bases are divided, we have to put only one base and subtract the powers.

= 103 - q

Problem 12 :

(c4)m

Solution :

(c4)m

Since we have power raised by another power, we have to multiply the powers.

= c4m

Problem 13 :

(6x2) (4x2)

Solution :

(6x2) (4x2)

First we have to multiply signs, then multiply the coefficients. Finally multiply the variables.

= 6 (4) x2x2

= 24 x2 + 2

= 24 x4

Problem 14 :

(3x3y2)(-6 y5)

Solution :

(3x3y2)(-6 y5)

First we have to multiply signs, then multiply the coefficients. Finally multiply the variables.

= 3 (6) xy2 y5

= 24 x2 + 2

= 24 x4

= 24 x4

Problem 15 :

 (5p3)(-m8 p2)

Solution :

 (5p3)(-m8 p2)

First we have to multiply signs, then multiply the coefficients. Finally multiply the variables.

= 5(-1) p3p2m8

= -5 p2+3m8

= -5 p5m8

Problem 16 :

 (10gh8 v6) (11g h8)

Solution :

  (10gh8 v6) (11g h8)

First we have to multiply signs, then multiply the coefficients. Finally multiply the variables.

= 10 (11) g3 · h8· h8 v6

= 110 g(3 + 1) h(8+8)v6

= 110 gh16v6

Problem 17 :

(4 fh3) (-5 f6) (-3 h2

Solution :

= (4 fh3) (-5 f6) (-3 h2

First we have to multiply signs, then multiply the coefficients. Finally multiply the variables.

= 4(-5)(-3) f9 · f6 h3 · h2

= -60 f9+6 h3+2

= -60 f15 h5

Problem 18 :

(-22 x3 y4)((-3)2 x4 y4)

Solution :

= (-22 x3 y4)((-3)2 x4 y4)

First we have to multiply signs, then multiply the coefficients. Finally multiply the variables.

= 4(-3)2x3 · xy3 · y

= 36 x3+4 y3+4

= 36 x7 y7

Problem 19 :

(3 xa yb zc )(-yf zg )

Solution :

=  (3 xa yb zc )(-yf zg )

First we have to multiply signs, then multiply the coefficients. Finally multiply the variables.

= 3(-1) x yzczg

= -3 x yzc+g

Problem 20 :

(x2 y)4

Solution :

= (x2 y)4

Here we have to distribute the power for all the terms which are inside the bracket.

= (x2)4 y4

Since we have power raised by another power, we have to multiply the powers.

x2(4) y4

= x8 y4

20)  

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