Problem 1 :
∫ 6θ cos (3θ2) dθ
Solution :
Let t = 3θ2
dt = 3(2θ) dθ
dt = 6θ dθ
∫ 6θ cos (3θ2) dθ = ∫ cos (t) dt
= sin t + C
= sin (3θ2) + C
Problem 2 :
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May 21, 24 08:51 PM
May 21, 24 08:51 AM
May 20, 24 10:45 PM