By table,
By graph,
Example 1 :
Describe the location of the point.
(i) J(2, 3) (ii) K(-5, -1) |
(iii) L(0, -3) (iv) M(4, -4) |
Solution :
By observing the above graph,
(i) J(2, 3) is located at Quadrant I.
(ii) K(-5, -1) is located at Quadrant III.
(iii) L(0, -3) is located at y-coordinate.
(iv) M(4, -4) is located at Quadrant IV.
Example 2 :
What is the x-coordinate of the point (-12, 7)? What is the y-coordinate?
Solution :
The x-coordinate of the point is -12.
The y-coordinate of the point is 7.
Example 3 :
A point has one positive coordinate and one negative coordinate. Can you determine in which quadrant the point lies? Explain.
Solution :
If the point has one positive coordinate and one negative coordinate that is located at Quadrant IV.
Example 4 :
Give the coordinates of the point.
(i) A (ii) B (iii) C (iv) D |
(v) E (vi) F (vii) G (viii) H |
Solution :
By observing the above graph,
The coordinates of Point A are (-4, 2).
The coordinates of Point B are (0, 3).
The coordinates of Point C are (0, 0).
The coordinates of Point D are (4, 0).
The coordinates of Point E are (-2, -4).
The coordinates of Point F are (3, 3).
The coordinates of Point G are (4, 4).
The coordinates of Point H are (-3, -2).
Example 5 :
Use the variable expression 2x + 1.
a) Evaluate the expression when x = -3, -2, -1, 0, 1, 2, and 3
b) Use your results from part (a) to write a list of ordered pairs in the form (x, 2x + 1).
Solution :
a)
Given, expression 2x + 1
when x = -3 = 2(-3) + 1 = -6 + 1 = -5 |
when x = -2 = 2(-2) + 1 = -4 + 1 = -3 |
when x = -1 = 2(-1) + 1 = -2 + 1 = -1 |
when x = 0 = 2(0) + 1 = 0 + 1 = 1 |
when x = 1 = 2(1) + 1 = 2 + 1 = 3 |
when x = 2 = 2(2) + 1 = 4 + 1 = 5 |
when x = 3 = 2(3) + 1 = 6 + 1 = 7 |
b)
write a list of ordered pairs in the form (x, 2x + 1)
From (a),
(-3, -5) (-2, -3) (-1, -1) (0, 1) |
(1, 3) (2, 5) (3, 7) |
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