HOW TO MULTIPLY BINOMIAL RADICAL EXPRESSIONS

Expand and simplify :

Problem 1 :

(1 + √2) (2 + √2)

Solution :

(1 + √2) (2 + √2)

= 1 ⋅ 2 + 1√2 + 2√2 + √2 ⋅ √2

= 2 + 3√2 + 2

= 4 + 3√2

Problem 2 :

(2 + √3) (3 + √3)

Solution :

(2 + √3) (3 + √3)

= 2 ⋅ 3 + 2√3 + 3√3 + √3 ⋅ √3

= 6 + 5√3 + 3

= 9 + 5√3

Problem 3 :

(√3 + 2) (√3 – 1)

Solution :

(√3 + 2) (√3 – 1)

 = √3 ⋅ √3 - √3 ⋅ 1 + 2√3 – 2

= 3 - √3 + 2√3 – 2

= 1 + √3  

Problem 4 :

(4 - √2) (3 + √2)

Solution :

(4 - √2) (3 + √2)

= 4 ⋅ 3 + 4√2 - 3√2 - √2 ⋅ √2

= 12 + √2 – 2

= 10 + √2

Problem 5 :

(1 + √3) (1 - √3)

Solution :

(1 + √3) (1 - √3)

= (1)² – (√3)²

= 1 – 3

 = -2

Problem 6 :

(5 + √7) (2 - √7)

Solution :

(5 + √7) (2 - √7)

= 5 ⋅ 2 – 5√7 + 2√7 - √7 ⋅ √7

= 10 - 3√7 – 7

= 3 - 3√7

Problem 7 :

(√5 + 2) (√5 – 3)

Solution :

(√5 + 2) (√5 – 3)

= √5 ⋅√5 - √5 ⋅ 3 + 2 ⋅√5 – 6

= 5 - 3√5 + 2√5 – 6

= -1 - √5    

Problem 8 :

(6 - √3) (2 + √3)

Solution :

(6 - √3) (2 + √3)

= 6 ⋅ 2 + 6√3 - 2√3 - √3 ⋅√3

= 12 + 4√3 – 3

= 9 + 4√3

Problem 9 :

(4 - √2) (3 - √2)

Solution :

(4 - √2) (3 - √2)

 = 4 ⋅ 3 – 4√2 - 3√2 + √2 ⋅√2

= 12 - 7√2 + 2

= 14 - 7√2

Problem 10 :

(4 - 3√3) (2 - √3)

Solution :

(4 - 3√3) (2 - √3)

= 4 ⋅ 2 - 4√3 - 3√3 ⋅ 2 + 3√3 ⋅√3

= 8 - 4√3 - 6√3 + 3 ⋅ 3

= 8 - 10√3 + 9

= 17 - 10√3

Problem 11 :

(-1 + 2√2) (2 - √2)

Solution :

(-1 + 2√2) (2 - √2)

= -1 ⋅ 2 + 1 ⋅ √2 + 2√2 ⋅ 2 - 2√2 ⋅√2

= -2 + √2 + 4√2 – 2 ⋅ 2

= -2 + 5√2 – 4

= -6 + 5√2

Problem 12 :

(2√2 + 3) (2√2 + 5)

Solution :

(2√2 + 3) (2√2 + 5)

= 2√2 ⋅ 2√2 + 2√2 ⋅ 5 + 3 ⋅ 2√2 + 3 ⋅ 5

= 2 ⋅ 2 ⋅√2 ⋅ √2 + 2 ⋅ 5√2 + 3 ⋅ 2√2 + 3 ⋅ 5

= 4 ⋅ 2 + 10√2 + 6√2 + 15 

= 8 + 10√2 + 6√2 + 15

= 23 + 16√2