To find nth term of the arithmetic sequence, we use the formula
an = a1 + (n – 1)d
Here a1 is the first term, n represents the position of the term and d represents the common difference.
Find the nth
term of the sequence, then find the 20th term.
Problem 1 :
a1 = 2 and d = 3
Solution :
a1 = 2 and d = 3
To find the nth term of the sequence :
an = a1 + (n – 1)d
an = 2 + (n – 1)(3)
an = 2 + 3n – 3
an = 3n – 1
To find the 20th term of the sequence :
an = 3n – 1
a20 = 2 + (20 – 1)3
a20 = 2 + (19)3
= 2 + 57
a20 = 59
So, the 20th term is a20 = 59.
Problem 2 :
-6, -4, -2, …
Solution :
-6, -4, -2, …
an = a1 + (n – 1)d
d = a2 – a1 = -4 + 6 =
2
= a3 – a2 = -2 + 4 = 2
To find the nth term of the sequence :
an = -6 + (n – 1)2
= -6 + 2n – 2
an = 2n – 8
To find the 20th term of the sequence :
a20 = 2(20) – 8
= 40 – 8
a20 = 32
So, the 20th term is a20 = 32.
Problem 3 :
a1 = 0 and d = 2/3
Solution :
a1 = 0 and d = 2/3
To find the nth term of the sequence :
an = a1 + (n – 1)d
an = 0 + (n – 1)(2/3)
an = (2/3)(n – 1)
To find the 20th term of the sequence :
a20 = 0 + (20 – 1)2/3
a20 = (19)2/3
a20 = 38/3
So, the 20th term is a20 = 38/3.
Problem 4 :
2/5, 1/15, -4/15, …
Solution :
2/5, 1/15, -4/15, …
an = a1 + (n – 1)d
d = a2 – a1 = 1/15 –
2/5
= 1/15 – 2/5 × (3/3)
= 1/15 – 6/15
= -5/15
= -1/3
To find the nth term of the sequence :
an = 2/5 + (n – 1)(-1/3)
To find the 20th term of the sequence :
an = 2/5 + (n – 1)(-1/3)
a20 = 2/5 + (20 – 1)(-1/3)
a20 = 2/5 + 19(-1/3)
a20 = 2/5 + (-19/3) (5/5)
= (6/15) - (95/15)
= (6 - 95)/15
a20 = -89/15
So, the 20th term is a20 = -89/15.
May 21, 24 08:51 PM
May 21, 24 08:51 AM
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