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If two shapes are similar, then their perimeter are proportional to the measures of the corresponding sides.
More simply, if two shapes are in the ratio a : b, then its perimeter will also be in the ratio a : b.
If two shapes are in the ratio a : b, then its area will be in the ratio a2 : b2.
Problem 1 :
Triangle HIJ is similar to triangle STR, what is the perimeter of triangle STR

Solution :
Since the given sides are similar,
HI : ST = 4 : 10
HI : ST = 2 : 5
|
IJ : TR = 2 : 5 6 : TR = 2 : 5 6/TR = 2/5 TR = 15 |
HJ : SR = 2 : 5 HJ : 12 = 2 : 5 HJ/12 = 2/5 HJ = 24/5 |
Perimeter of STR :
= ST + TR + SR
= 10 + 15 + 12
= 37
Problem 2 :
If the two triangles are similar

Find
i) Scale factor
ii) Ratio of perimeter
iii) Ratio of area
Solution :
The sides which are having side lengths 21 and 7, they are corresponding sides.
The sides lengths 15 and 5 are corresponding, then 18 and 6 are corresponding.
Ratio = 21 : 7 ==> 3 : 1
i) Scale factor = 3 : 1
ii) Ratio of perimeter = 3 : 1
iii) Ratio of area = 32 : 12
Problem 3 :
Two triangles have a scale factor of 2/3. The area of the larger triangle is 12 cm2. What is the area of smaller triangle.
Solution :
Area of smaller triangle / Area of larger triangle = (2/3)2
Area of larger triangle = 12 cm2
Area of smaller triangle / 12 = (2/3)2
Area of smaller triangle = 12 (4/9)
Area of smaller triangle = 5.3 cm2
Problem 4 :
If the length of each side of triangle is cut to 1/3 of its original size, what happens to the area of the triangle ?
The new area is _______________ of the original area.
Solution :
From the given information, every side is being divided into 1/3 of the original size. So, the ratio is 1 : 3.
Relationship between scale factor and area :
Area of smaller triangle : Area of larger triangle = (1 : 3)2
Area of smaller triangle : Area of larger triangle = 1 : 9
Area of smaller triangle = (1/9) of area of larger triangle.
Problem 5 :
For the two triangles below to be similar, which of the following be true ?

a) x = 2y/3 b) c = 3y/2 c) x = 3y d) x = y
Solution :
Since the given shapes are similar,
EF : KJ ==> 6 : 9 ==> 2 : 3
FG : KL ==> x : y
x : y = 2 : 3
x/y = 2/3
x = 2y/3
Problem 6 :
An architect is building a model of a tennis court for a new client. On the model, the court is 6 inches wide and 13 inches long. An official tennis court is 36 feet wide. What is the length of a tennis court ?
Solution :
Let x be the length of tennis court.
Since the shapes are similar, the ratio between model to official tennis court is
6 : 13 = 36 : x
6/13 = 36/x
6x = 36(13)
x = 36(13)/6
x = 6 (13)
x = 78
So, length of official tennis court is 78 feet.
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